Sort random number at a matrix

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Guilherme Lopes de Campos
回答： Dyuman Joshi 2023-9-26
Dear community,
I would like to sort a matrix size (4998x2) on random form.
The follow code it was used:
n=4998
Matrixw = repmat(x, 1, ceil(n/numel(x)));
Matrixw = Matrixw(randperm(n));
The head of data is:
TT Test1
TT Test2
TT Test3
TT Test4
CN Test5
CN Test6
CN Test7
CN Test8
CN Test9
CN Test10
SN Test11
SN Test12
SN Test13
SN Test14
SN Test15
SN Test16
SN Test17
Using the code above, just first column is random sort, but, I need that respectivly both column of the matrix are random sort, in the other words:
SN Test17
TT Test4
CN Test7
Each pair of variable is random sort, but together.
Can help me, please?
Yours faithfully

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采纳的回答

Voss
Voss 2023-9-26
Ran in:
% a matrix
M = reshape(1:100,[],2)
M = 50×2
1 51 2 52 3 53 4 54 5 55 6 56 7 57 8 58 9 59 10 60
% randomly reorder the rows
M = M(randperm(size(M,1)),:)
M = 50×2
3 53 33 83 31 81 42 92 18 68 27 77 37 87 29 79 24 74 16 66

更多回答（1 个）

Dyuman Joshi
Dyuman Joshi 2023-9-26
Ran in:
Do you mean like this -
n = 10;
x = [(1:10)' (10:-1:1)']
x = 10×2
1 10 2 9 3 8 4 7 5 6 6 5 7 4 8 3 9 2 10 1
idx = randperm(n)
idx = 1×10
1 6 3 5 4 9 8 10 2 7
x = x(idx,:)
x = 10×2
1 10 6 5 3 8 5 6 4 7 9 2 8 3 10 1 2 9 7 4

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