rotate 3D data

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Lotte Piek
Lotte Piek 2023-10-18
评论： Star Strider 2023-10-18
I have a geometry that consists of contours of xyz data points, I want to allign it in such a way that the inlet(left side) is perpendicular to the z axis so that the lenght of the geometry is along the z-axis. Can anybody help?
Thanks!
  2 个评论
Dyuman Joshi
Dyuman Joshi 2023-10-18
How is your question related to MATLAB?
Do you attain the figure by MATLAB code? If so, then provide the code and relevant data used.
Lotte Piek
Lotte Piek 2023-10-18
编辑：Lotte Piek 2023-10-18
for i=101:171;
plot3(dab.SegmentInfo(i).branch1(:,1), dab.SegmentInfo(i).branch1(:,2),dab.SegmentInfo(i).branch1(:,3)); hold on; --> blue in image
plot3(dab.SegmentInfo(i).branch2(:,1), dab.SegmentInfo(i).branch2(:,2),dab.SegmentInfo(i).branch2(:,3)); hold on; --> green in image
end;
for i = 173:435
plot3(dab.SegmentInfo(i).main(:,1), dab.SegmentInfo(i).main(:,2),dab.SegmentInfo(i).main(:,3)); --> black in image
end
Colours in the figure are after the line, so the data consists of three parts and these consist of countours (xyz values for the points in the contours)

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采纳的回答

Star Strider
Star Strider 2023-10-18
Ran in:
Use the rotate function. It will likely require a bit of experimenting to get it the way you want it.
Example —
imshow(imread('ask.png'))
title('Question Image')
x = 0:0.01:2*pi;
y = sin(8*x);
z = cos(8*x);
figure
hp = plot3(x, y, z);
grid on
xlabel('x')
ylabel('y')
zlabel('z')
axis('square')
title('Original')
figure
hp = plot3(x, y, z);
grid on
xlabel('x')
ylabel('y')
zlabel('z')
axis('square')
rotate(hp,[0 1 0],90)
title('Rotated')
.
  2 个评论
Lotte Piek
Lotte Piek 2023-10-18
thanks, will give it a try!
Star Strider
Star Strider 2023-10-18
As always, my pleasure!

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