problem with if statement

4 次查看(过去 30 天)
NS
NS 2011-11-4
Hi Guys,
This is a very basic question. I want to figure out which quadrant a point lies in from the value I get from atan2. I dont know if there is a simpler way but I wrote a code containing a series of if statements and it isnt executing right. Can anyone tell me what is wrong in it. Your help is greatly appreciated.
if 0<ang<1.5708
quad=1;
end
if 1.5708<ang<3.1416
quad=2;
end
if -1.5708<ang<0
quad=3;
end
if -3.1416<ang<-1.5708
quad=4;
end
Thanks, NS
  1 个评论
sco1
sco1 2011-11-4
I'll look at it in a second, but I would suggest using pi() instead of discrete numbers in order to avoid errors where your point lies on one of the axes.

请先登录,再进行评论。

采纳的回答

Wayne King
Wayne King 2011-11-4
if (0<ang && ang <1.5708)
quad=1;
elseif (1.5708<ang && ang<3.1416)
quad=2;
elseif (-1.5708<ang && ang<0)
quad=3;
else
quad=4;
end
You can't do 0<ang<pi/2

更多回答(2 个)

Fangjun Jiang
Fangjun Jiang 2011-11-4
What is wrong is that "0<ang<1.5708" is not a valid statement according MATLAB M-language syntax. You will need to use
and(0<ang, ang<1.5708)
Or
0<ang && ang<1.5708
  1 个评论
NS
NS 2011-11-4
Oh I didnt know that. Thanks I will change my code :)

请先登录,再进行评论。


sco1
sco1 2011-11-4
I don't think MATLAB will handle the logic statements when put that way, try using an and statement instead: I would also suggest using elseif just because it makes things look neater.
For example:
if ang > a && ang < b
quad = x
elseif ang > b && ang < c
quad = y
etc.
edit: I'm a slow typer!

类别

Help CenterFile Exchange 中查找有关 Annotations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by