Numerical error in simulink
6 次查看(过去 30 天)
显示 更早的评论
采纳的回答
Paul
2023-11-20
Hi Junghyo Kim,
Your question references "division by 0" but the error message has nothing to do with division by zero.
The error message clearly sates that the problem occurs at T = 0.128 and that, at that time, the solver can't solve an algebraic loop in the model. See Algebraic Loop Concepts if you're not familiar and the Related Topics at the bottom of that page as a starting point.
0 个评论
更多回答(1 个)
Walter Roberson
2023-11-20
编辑:Walter Roberson
2023-11-20
When the error is at time 0, as is the case in your example, then the problem is almost always incorrect initial values.
Consider for example if you have a derivative block. At time 0, no time has elapsed so far so the "natural" outcome right at time 0 is either 0 change divided by 0 seconds (0/0 giving NaN) or else some finite change divided by 0 seconds (giving +/- infinity). So for derivative blocks and similar it is crucial that you define the initial conditions.
Likewise if you have any calculation in your model that divides something by clock time, the calculation is in trouble at time 0.
1 个评论
Paul
2023-11-20
The error occurred at T = 0.128, not T = 0, so it's not an issue with initial conditions at the start of the simulation.
Also, the Derivative Block does not work that way; it always outputs 0 as its initial output. As far as I know, the Derivative block doesn't have an initial condition to specify.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 General Applications 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!