Identifying straight line & intersection with the curve from the binary image

1 次查看(过去 30 天)
I want to fit a blue line (curved or straight), detect a red line, and then find the slope of the light green line that is tangent to the blue line at the intersection of the two lines.
By detecting the first row in each column with the value 1, I could detect blue line.
Also, fitting blue curvature from this data would be no problem.
In the case of a straight line section, it seems to be possible to first find the row with a value of 1 for each column, average it, and then draw a straight line to the value on the leftmost side.
However, in this case, it seems that I have to manually determine the location of the pixel corresponding to the straight line section(otherwise, even curved surfaces will be recognized).
Any suggestion would be very helpful.
Thank you.

采纳的回答

Image Analyst
Image Analyst 2023-11-23
The best solution is if you can put your part into some kind of jig so that everything is in a fixed, known position. Then you can just use a fixed mask to erase everything you don't want.
Another way might be to scan the image row by row using find() and find out where that large rectangular gap is. Then just erase 3 or 4 columns just to the outside of the rectangular gap.
Another option would be to scan the image getting the top rows and then try to find the change point using findchangepts.
Another option would be to just fit everything, spike and all, then find the residuals between your fit and the actual data and say that if the residual (difference) is too much, then delete those points and train your polynomial again.
  1 个评论
DW
DW 2023-11-28
Unfortunately, the 'best solution' is unlikely to be available.
I'm trying the rest of the methods.
Thanks for the answer.

请先登录,再进行评论。

更多回答(1 个)

Matt J
Matt J 2023-11-23
编辑:Matt J 2023-11-23
load BWimage
C=bwareafilt(BW&~imopen(BW,ones(1,8)),1);
[I,J]=find(C);
x=mean(J); y=max(I); %intersection coordinates
imshow(BW); hold on
scatter(x,y,'r','filled'); hold off
  3 个评论

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Image Processing Toolbox 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by