identifying and isolating consecutive numbers

Question

Katerina F 2024-2-16

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2083043-identifying-and-isolating-consecutive-numbers

编辑： Matt J 2024-2-17

采纳的回答： Matt J

在 MATLAB Online 中打开

I found the following questions in Matlab which is similar to mine

I have a vector, for example, A= [1 2 3 4 14 15 23 24 25 ]

and I want a code that will identify regions of consecutive numbers and separate them into their own array. ie, a code that will split A into

B = [1 2 3 4] C = [14 15] D = [23 24 25]

I would like this code to be able to work on a matrix A of variable length. Any suggestions?

..................I tryed an answer that worked in the first place but then was giviing me an error. The answer and the error are below

MATLAB ANSWER:

A= [1 2 3 4 14 15 23 24 25 ]
A = 1x9
     1     2     3     4    14    15    23    24    25
assert(size(A,1)==1 && isa(A,'double'));
p=find(diff(A)>1);
ind=[A(1),A(p+1);A(p),A(end)]
ind = 2x3
     1    14    23
     4    15    25

% ind =

% 1 14 23

% 4 15 25

ERROR

Operands to the logical AND (&&) and OR (||) operators must be convertible to

logical scalar values. Use the ANY or ALL functions to reduce operands to logical

scalar values.

...

What could I do to rectify please? Thanks

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Walter Roberson 2024-2-16

That code is not producing that error?

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Answer 1

Matt J 2024-2-16

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2083043-identifying-and-isolating-consecutive-numbers#answer_1410618

编辑：Matt J 2024-2-17

在 MATLAB Online 中打开

code that will split A into B = [1 2 3 4] C = [14 15] D = [23 24 25]

It would be a bad idea to split A into separate variables, but you can split it in cell array form as follows:

A= [1 2 3 4 14 15 23 24 25 ];
D=find(  diff([A,inf])~=1   );
Asplit=mat2cell(A,1,[D(1), diff(D) ] ) ;  %the final result
Asplit{:}
ans = 1×4
     1     2     3     4
ans = 1×2
    14    15
ans = 1×3
    23    24    25

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Dyuman Joshi 2024-2-17

在 MATLAB Online 中打开

A similar approach -

A = [1 2 3 4 14 15 23 24 25];
idx = [find(diff(A)~=1) numel(A)];
out = mat2cell(A, 1, [idx(1) diff(idx)])
out = 1x3 cell array
    {[1 2 3 4]}    {[14 15]}    {[23 24 25]}