Trouble using diffuse function
1 次查看(过去 30 天)
显示 更早的评论
Hello, I'm trying to use the diffuse() function to simulate Lamburtian reflectance off a surface and the help page leaves a bit to be desired. I'm having several errors running the function and was just hoping someone could provide me with an example use of the function so that I can confirm the syntax I'm using is correct.
My end goal is to calculate the reflected light off the surface and compare it to the light that continues past the target and reflects off a second surface. Any help would be greatly appreciated.
0 个评论
采纳的回答
Florian Bidaud
2024-3-11
编辑:Florian Bidaud
2024-3-11
The structure is:
R = diffuse(Nx,Ny,Nz,S)
The output R is defined with Lambert's Law by R = cos(psi) where psi is the angle between the surface normal and light source.
If you have a surface on the (x,y) plan, the normal vector is [Nx,Ny,Nz] = [0,0,1].
S = [Theta Phi] is the direction vector of the light source in spherical coordinates (in degrees).
For example
S = [10 45];
R = diffuse(0,0,1,S)
You can also define S in the (x,y,z) coordinates. That would give, to have the same output:
S = [sind(45)*cosd(10) sind(45)*sind(10) cosd(45)];
R = diffuse(0,0,1,S)
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Surface and Mesh Plots 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!