identify different filname in different group

2015 4 17
4 个回答
回答已采纳
更新时间：2015 4 22
6 次查看（30 天）

0 个投票

Hello,
I just realized a program that allows to load data files from a folder. These data files are all different names but I would group them into three groups in matlab. A group 1 whose file names begin with 'X', a group 2 whose file names begin with 'Y' and a group 3 whose file names begin with 'Z' but I do not know how. Do you have any idea? with strcmp?

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Alexandre Williot
Alexandre Williot 2015-4-22

0 个投票

this is what I needed,
contenu = dir('C:\Users\alexandre\Dropbox\UQTR 2013 - 2015\Matlab\MatLab EPK6064\Fichiers_Travail2');
for file = 1:length(contenu)
Fichiers_Travail2 = contenu(file).name;
if strcmp(Fichiers_Travail2,'.')==0 && strcmp(Fichiers_Travail2,'..')==0 && strcmp(Fichiers_Travail2(1,1),'e')==0
load(Fichiers_Travail2)
if strcmp(Fichiers_Travail2(1,1),'S')==1
code_Groupe = 1;
elseif strcmp(Fichiers_Travail2(1,1),'C')==1
code_Groupe = 2;
elseif strcmp(Fichiers_Travail2(1,1),'L')==1
code_Groupe = 3;
end
end
end

更多回答（3 个）

pfb
pfb 2015-4-17

0 个投票

It's not very clear to me what you mean by "group the files in matlab".
Anyway, one possibility is perhaps to discriminate them before loading them. I suppose you use dir to make a list of the files to be loaded. Why don't you use something like
dirX = dir('X*');
dirY = dir('Y*');
dirZ = dir('Z*');
or something to that effect? I mean, you might have to refine the string you feed to dir(), possibly adding a path or using some more information about the file names.
Anyway, now dirX, dirY and dirZ are structures containing the names of the files starting with the desired letter.
Image Analyst
Image Analyst 2015-4-21

0 个投票

Of course, because you're passing the whole structure:
file_name = contenu(file).name;
load(contenu) % Tries to load the entire structure of all filenames.
Instead, try to load only one filename:
file_name = contenu(file).name;
load(file_name) % Tries to load only one single filename.

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Alexandre Williot
Alexandre Williot 2015-4-21
编辑：Alexandre Williot 2015-4-21
Of course ! I am a beginner, thank you very much.
Now I have this message for the code below, have you an idea please? It's probably easy but ... not for me.
??? Error using ==> strcmp
Not enough input arguments.
Error in ==> exercice2__a_williot at
20
if strcmp(contenu(file).name,'S')==1
the code
contenu = dir('C:\Users\williot\Dropbox\UQTR 2013 - 2015\Matlab\MatLab EPK6064\Fichiers_Travail2');
for file = 1:length(contenu)
if strcmp(contenu(file).name,'.')==0 && strcmp(contenu(file).name,'..')==0
file_name = contenu(file).name;
load(file_name)
end
end
%--étape2--identifiez chaque groupe de personne-------
if strcmp(contenu(file).name,'S')==1
code_Groupe = 1;
elseif strcmp(contenu(file).name,'C')==1
code_Groupe = 2;
elseif strcmp(contenu(file).name,'L')==1
code_Groupe = 3;
end
Image Analyst
Image Analyst 2015-4-22
file is no longer defined because the for loop over "file" has ended by the time you call your next if block in etape2. I guess you probably want it INSIDE your for loop, not outside.
Image Analyst
Image Analyst 2015-4-22
By the way, you were supposed to accept my answer, not post your code and accept it.

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