Square wave by vector multiplication

2 次查看(过去 30 天)
I'm trying to build a square wave by using vector multiplication instead of using the "for" loop. It was suggested as multiply a 1xn vector with a nx1 vector. Here is my code constructing the square wave using the "for" loop:
N = 13;
f = 1000 * sin(2 * pi / (49 * N));
t = 0:0.0001:1;
n = 100;
A = 2;
square_wave = zeros(size(t));
for k = 1:n
if mod(k, 4) == 1
a_k = 4 * A / (k * pi);
elseif mod(k, 4) == 3
a_k = -4 * A / (k * pi);
else
a_k = 0;
end
square_wave = square_wave + a_k * cos(k * 2 * pi * f * t);
end
plot(t, square_wave);
xlabel('Time (s)');
ylabel('Amplitude');
title('Square Wave Approximation');
grid on

采纳的回答

Voss
Voss 2024-3-30
k = (1:n).';
a_k = repmat([1;0;-1;0],n/4,1)*4*A./(k*pi);
square_wave = sum(a_k .* cos(k .* 2 * pi * f * t),1);
  2 个评论
David
David 2024-4-1
I tried to run the code above and it is reported error:
Error using .*
Matrix dimensions must agree.
square_wave = sum(a_k .* cos(k .* 2 * pi * f * t),1);
I assume the dimension of two matrices is not suitable for multiplication.
Do you have any idea how to fix this?
Voss
Voss 2024-4-1
编辑:Voss 2024-4-1
This runs for me:
N = 13;
f = 1000 * sin(2 * pi / (49 * N));
t = 0:0.0001:1;
n = 100;
A = 2;
k = (1:n).';
a_k = repmat([1;0;-1;0],n/4,1)*4*A./(k*pi);
square_wave = sum(a_k .* cos(k .* 2 * pi * f * t),1);
plot(t, square_wave)
Double-check that you are running the same code.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by