Matlab cannot recognize variable
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I have this code here.
%May change entire thing to function
clc;
clear;
%Variables
sigma = .1;
lock = 8;
twist = -8;
a = 5.7*(180/pi);
bloading = .12;
mu = .25;
alpha_tpp = 2.25;
siga = sigma*a; % This variable is seen a lot.
%% solve for inflow
% Change
CT = .0012;
lambdaH = sqrt(CT/2);
muz = mu*tand(alpha_tpp);
aproxerr = 10^5;
esterr = 100;
n = 0;
f = .5;
while aproxerr < esterr
n = n+1;
if n == 1
lambdaold = lambdaH;
else
lambdaold = lambda;
end
%iterating on
lambdain = lambdaH^2/(sqrt(lambdaold^2+mu^2));
lambda = lambdaold - (lambdaold - muz - lambdain)/(1+((lambdain*lambdaold)/(lambdaold^2+mu^2)))*f;
esterr = abs(lambda - lambdaold)/lambda;
end
%% Question 2
delta = 1 - mu^2 + (9/4*mu^4);
%theta_collective =
%(1/delta)*((1+((3/2)*mu^2)))*((6*CT)/(sigma*a)+(.375*mu^2*twist) I
%do not know if this is necessary
Betanaught = ((lock/8)/delta)*(1-((19/18)*mu^2)+(1.5*mu^4))*((6*CT)/siga)+(.005+((29/120)*mu^2)-(.2*mu^4)+(.375*mu^6))*twist + lambda*((1/6)-((7/12)*mu^2)+(.25*mu^4));
Why is Lambda unrecognized here? I ran another code that had pretty much the same iteration up until the end of the while loop, and lambda was defined in it. So what is wrong here? And btw, I appreciate all the help you guys offer me.
Other code for reference
format long
% lambda is x
Rmain=27; %ft
Cmain=1.7; %ft
Nbmain=4;
Tipspeed_main=725; %ft/s
W=16000; %lb
alt=5000;
alpha_tpp=3;
%knots
%%
Amain=pi*Rmain^2;
sigma=(Nbmain*Cmain)/(pi*Rmain);
[~, ~, ~, RHO] = atmosisa(alt*0.3048);
rho=RHO*0.0685218/35.3147;
CT = W/(rho*Amain*Tipspeed_main^2);
xh = sqrt(CT/2);
V = 0*1.68781:10*1.68781:200*1.68791;
Mu = V./(Tipspeed_main);
for k1=1:length(Mu)
mu=Mu(k1);
muz = mu*tand(alpha_tpp);
n = 0;
aperr = 10^-5;
eserr = 100;
while eserr > aperr
n = n + 1;
if n == 1
xold = xh;
else
xold = x ;
end
%iterating on
xin = xh.^2./sqrt(xold.^2+mu.^2);
x = xold - (xold - muz - xin)./(1+((xin.*xold)./(xold.^2+mu.^2))).*.5;
eserr = abs((x - xold)./x);
end
X(k1)=x;
end
figure
plot(Mu,X,'-x')
grid on
采纳的回答
Dyuman Joshi
2024-4-2
编辑：Dyuman Joshi
2024-4-2
"Why is Lambda unrecognized here?"
Because the while loop is not initiated, as the condition is not satisfied.
As the while loop does not run, lambda is not defined.
And when you use lambda (undefined parameter) to define Betanaught, it gives you the aforementioned error.
aproxerr = 10^5;
esterr = 100;
while aproxerr < esterr
...
end
Maybe aproxerr is 10^-5 (or something else). Correct the value and your code will run (I tested with couple of smaller values 10^0, 10^-1, etc).
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