How do I save vector values from for loop?

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Jaevon Stewart
Jaevon Stewart 2024-4-4
评论： Voss 2024-4-4
I have this section of code here
az = 0:90:270;
for k = 1:length(az)
rR = 0:.1:1;
L1 = (rR.*rR.*.5)+(mu.*rR.*thetanaught.*sind(az(k)))+(.5.*thetanaught.*mu.^2.*sind(az(k)).^2)+(.5.*twist.*rR.^3)+(mu.*twist.*rR.^2.*sind(az(k)))+(.5.*twist.*mu^2.*rR.*sind(az(k)).^2)+(.5.*rR.^2.*Theta_1c.*cosd(az(k)))+(rR.*mu.*Theta_1c.*sind(az(k)).*cosd(az(k)));
L2 = (.5.*rR.^2.*Theta_1s.*sind(az(k)))+(.5.*mu.^2.*Theta_1s.*sind(az(k)).^3)-(.5.*lambda.*rR)-(.5.*mu.*lambda.*sind(az(k)))-(.5.*rR.*mu.*Beta.*cosd(az(k)))-(.5.*mu.^2*Beta.*cosd(az(k)).*sind(az(k)));
Lc = L1+L2
end
I want to be able to plot Lc for each of the az values. So it looks something like this.
What is an efficient way to get matlab to store the vectors from each loop so I can do this? The way I was doing it before was just saving the values and I ended up with a 1x44 vector.

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采纳的回答

Voss
Voss 2024-4-4
编辑：Voss 2024-4-4
az = 0:90:270;
rR = 0:0.1:1; % pull rR out of the loop (it never changes)
N = numel(az);
Lc = zeros(numel(rR),N); % make Lc a matrix with N columns
for k = 1:N
L1 = (rR.*rR.*0.5)+(mu.*rR.*thetanaught.*sind(az(k)))+(0.5.*thetanaught.*mu.^2.*sind(az(k)).^2)+(0.5.*twist.*rR.^3)+(mu.*twist.*rR.^2.*sind(az(k)))+(0.5.*twist.*mu^2.*rR.*sind(az(k)).^2)+(0.5.*rR.^2.*Theta_1c.*cosd(az(k)))+(rR.*mu.*Theta_1c.*sind(az(k)).*cosd(az(k)));
L2 = (0.5.*rR.^2.*Theta_1s.*sind(az(k)))+(0.5.*mu.^2.*Theta_1s.*sind(az(k)).^3)-(0.5.*lambda.*rR)-(0.5.*mu.*lambda.*sind(az(k)))-(0.5.*rR.*mu.*Beta.*cosd(az(k)))-(0.5.*mu.^2*Beta.*cosd(az(k)).*sind(az(k)));
Lc(:,k) = L1+L2; % store each result in a column of Lc
end
figure
plot(Lc) % plot N lines (each column of Lc is plotted as a separate line)

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