Why does this code give error?

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Sadiq Akbar
Sadiq Akbar 2024-4-16
评论： Sadiq Akbar 2024-4-22
Ran in:
clear;clc
%%
fc = 3e8;% Carrier frequency
Nb = 1000;% Number of snapshots
c = 3e8;
wavelength = c/fc;% The wavelength of the received signal
d = 0.5*wavelength;
theta = [5 40];
M = length(theta);% Number of signals
N = 10;% Number of antennas
% Wavenumber
beta = 2*pi/wavelength;
% Signal amplitude
A = 1;
% SNR (dB)
snr = 5;
% Variance of noise
sigma=sqrt((A^2)/(2*10^(snr/10)));
% Source signal
D = randi(M,Nb,1);
S =A*(2*D - 1);
% The electrical phase shift from element to element along the array
phi=beta*d*cos(theta*pi/180);
% Matrix of steering vectors
for i=1:M
for k=1:N;
VecteurDirectionnel(k,i)= exp(j*(k-1)*phi(i));
end
end
% White Gaussien noise
B = (sigma^2)*(randn(N,Nb)+j*randn(N,Nb))/sqrt(2);
% Array output:signal plus noise
X = VecteurDirectionnel*S+B;
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix. To operate on each element of the matrix individually, use TIMES (.*) for elementwise multiplication.
% Estimation of the spatial correlation matrix of the observed signal
Rxx = X*X'/Nb;
% Eigen decomposition
[Vi,Li] = eig(Rxx);
[L,I] = sort(diag(Li),'descend');
V = Vi(:,I);
Vs = V(:,1:M);
Vs1=Vs(1:N-1,:);
Vs2=Vs(2:N,:);
% Direction Of Arrival
% Least square
xsi=linsolve(Vs(1:N-1,:),Vs(2:N,:));
% DOA estimation
doa=acosd((angle(eig(xsi))/(2*pi*d)))

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采纳的回答

Matt J
Matt J 2024-4-16
编辑：Matt J 2024-4-16
Ran in:
As you can see, VecteurDirectionnel and S are the wrong sizes for matrix multiplication,
whos VecteurDirectionnel S
Name Size Bytes Class Attributes S 1000x1 8000 double VecteurDirectionnel 10x2 320 double complex
% Array output:signal plus noise
X = VecteurDirectionnel*S+B;
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix. To operate on each element of the matrix individually, use TIMES (.*) for elementwise multiplication.
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Matt J
Matt J 2024-4-19
Well S is Nb x 1 because D is Nb x 1, from this line,
D = randi(M,Nb,1);
Perhaps you meant to have,
D = randi([low, hi] , [M,Nb]);
but we have no way of knowing what you intended the low and hi limits to be.
Sadiq Akbar
Sadiq Akbar 2024-4-22
@Matt J
Thanks a lot for your help. Yes, you are right. It works now.

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