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Question

gyul 2024-5-1

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2113886-

移动：Angelo Yeo 2024-5-3

A=[2 3 4; 3 5 6; 1 3 2];
b=[7; 5; 9];
AM=[A, b];
n=size(AM);
nr=n(1);
nc=n(2);
b=AM(:,nc);
itr=1; max_itr=30; tolerance=0.03;
xn=zeros(3,1); X=zeros(max_itr,nr+2);
xo=[1;1;1];
while true
for i=1:1:nr
    s1=0; s2=0;
    if i~=1
        s1=AM(i,1:i-1)*xo(1:i-1);
    elseif i~=nr
        s2=AM(i,i+1:nr)*xo(i+1:nr);
    end
    s=s1+s2;
    xn(i)=(b(i)-s)/AM(i,i);
end
Re=abs(max(xn-xo)./xo);
if Re <= tolerance
    for i=1:1:nr
        fprintf('x(%d)=%f\n',i,xn(i));
    end
    break;
elseif itr > max_itr
    break;
else
    X(itr,:)=[itr,Re, xn'];
    itr=itr+1;
    xo=xn;
end
end
Error using horzcat
Dimensions of arrays being concatenated are not consistent.