Sum of Euclidean distances

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Lulu
Lulu 2011-11-14
Hi.
There are 5 points in 3D space: xyz=rand(5,3).
How can I quickly calculate a sum of Euclidean distances from the 1st point till the rest of points (2nd-5th)?
Thanks.

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采纳的回答

David Young
David Young 2011-11-14
diffs = bsxfun(@minus, xyz(2:end,:), xyz(1,:));
distance = sum(sqrt(sum(diffs.^2, 2)))

更多回答（1 个）

Grzegorz Knor
Grzegorz Knor 2011-11-14
sum((xyz(2:end,:)-repmat(xyz(1,:),size(xyz,1)-1,1)).^2,2).^0.5
or with loop;
for k=2:5
d(k-1) = norm(xyz(1,:)-xyz(k,:));
end

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