How can I make the layout in the attached image with tiledlayout

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AP
AP 2024-5-19
编辑： Matt J 2024-5-20
I am able to get plot 1 and plot 2 in but not 3, 4 and 5. I can also get 3, 4 and 5 in without plot 1 and 2 but that is not what I want, per the attached image.

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Star Strider
Star Strider 2024-5-19
编辑：Star Strider 2024-5-19
Ran in:
It took a few experiments to get this to work.
Try this —
x = 0:0.1:31;
y = sin((1:5).'*x*2*pi/32);
figure
tiledlayout(4,4)
nexttile([1 2])
plot(x,y(1,:))
grid
title('Plot 1')
nexttile([2 2])
plot(x,y(3,:))
grid
title('Plot 3')
nexttile([1 2])
plot(x, y(2,:))
grid
title('Plot 2')
nexttile([2 2])
plot(x, y(4,:))
grid
title('Plot 4')
nexttile([2 2])
plot(x, y(5,:))
grid
title('Plot 5')
EDIT — Corrected typographical errors.
.

更多回答（2 个）

Matt J
Matt J 2024-5-19
编辑：Matt J 2024-5-20
Ran in:
If you download nestedLayouts,
https://www.mathworks.com/matlabcentral/fileexchange/161736-grids-of-tiled-chart-layouts
then you can do,
x = 0:0.1:31;
y = sin((1:5).'*x*2*pi/32);
[ax,t]=nestedLayouts([2,2],[2,1]);
delete(ax([4,6,8]));
ax=ax([1,2,3,5,7]);
for k=1:numel(ax)
plot(ax(k), x,y(k,:));
title(ax(k), "Plot "+k);
if k>2, ax(k).Layout.TileSpan=[2,1]; end
end
for i=1:numel(t), ylabel(t(i),"YLabel "+i); end
Image Analyst
Image Analyst 2024-5-20
Ran in:
If you understand how subplots work, it's easy. The bottom and right plots just use a 2,2 layout while the upper left two use a 4,2 layout:
subplot(4, 2, 1);
title('Plot 1');
subplot(4, 2, 3);
title('Plot 2');
subplot(2, 2, 2);
title('Plot 3');
subplot(2, 2, 3);
title('Plot 4');
subplot(2, 2, 4);
title('Plot 5');
Many people don't realize it but whatever layout you use for your first subplot(s) does not need to be used for ALL subplots on the figure, so you can switch from 4 rows, 2 columns to 2 rows and 2 columns like I did above.

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