How to do counter in matlab?
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I want to do just like the following Matlab, it returns error, how to fix it so Matlab can take it without errors?
load M.dat
t = 600;
q(1)=[1;0;0;0;0;0;0;0;0;0];
for i=1:t-1,
q(i+1) = q(i)*M;
end
I want to have qt in the end. q(1) is a matrix called q1, and I want q2 which is q(i+1) to be M*q1 , and q3 to be M*q2 and visa versa until we reach qt
4 个评论
James Tursa
2015-4-21
Then q(i)*M is scalar*matrix, which is a matrix. How do you expect to store this into q(i+1), which is a scalar? You need to examine your equations and correct them to something that makes sense.
回答(3 个)
Image Analyst
2015-4-21
You can't assign a 10-element column vector to a single element of q. Only one element can go into the first element of q, not 10.
2 个评论
Image Analyst
2015-4-21
Try this:
M = 100 % Whatever...
t = 600;
q = zeros(1, t);
q(1)= 1;
for i=1:t-1,
q(i+1) = q(i)*M;
end
James Tursa
2015-4-21
I am still guessing here. Maybe this is what you want? (I am assuming M is square)
load M.dat
t = 600;
q = zeros(size(M,1),t);
q(1,1) = 1;
for k=2:t,
q(:,k) = M * q(:,k-1);
end
Each column of q is an intermediate answer, with q(:,t) being your final answer.
If you don't need all the intermediate answers, then simply
load M.dat
t = 600;
q1 = zeros(size(M,1),1);
q1(1) = 1;
qt = M^(t-1) * q1;
0 个评论
ALEX
2015-4-21
Hello,
Play around with this, let me know if you have problems.
clear all M = 1.1; t = 600; q1 = zeros(10,1); q1(1)= 1;
val = q1*M;
for i=1:t-1
eval(['q' num2str(i+1) ' = val ']);
val = val*M;
end
Peace
2 个评论
James Tursa
2015-4-22
Read this link to see why creating hundreds of variables q1, q2, ... etc in a loop is generally very bad programming practice:
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