Hypergeometric functions(1F2) in matlab
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I want to use the hypergeometric function [def] this exists in mathematica (wolfram). I tried this
function result = hypegeo(q, r)
qr = q * r;
z = - (qr)^2 / 4;
inp=[3/2,[1, 5/2],z];
F2_value = hypergeom(1,2,inp);
result = (1/3) * F2_value;
end
but for me looking at the definition of the hyper geometric function in matlab doesnt seem exaclty the same as the one in wolfram.
if they arent the same, is there a way to use mathmatica functions in matlab or some other workaround for this?
采纳的回答
Walter Roberson
2024-6-11
In MATLAB, some of the parameters are implicit according to the length of the other parameters.
function result = hypegeo(q, r)
qr = q * r;
z = - (qr)^2 / 4;
F2_value = hypergeom(3/2, [1, 5/2], z);
result = (1/3) * F2_value;
end
3 个评论
Walter Roberson
2024-6-11
No, mpmath.hyper accepts a, b, z parameters, where a and b are tuples. There is no hyper(a, b, c, z)
You should be using
a = 3/2;
b1 = 1;
b2 = 5/2;
z = -1*((q*r)^2)/4;
result_py = py.pyrun(mpmath.hyp1f2(a, b1, b2, z));
or something similar.
更多回答(1 个)
Shivani
2024-6-11
You can refer to the following file exchange link for implementation details of calculating a generalized Hypergeometric function: https://www.mathworks.com/matlabcentral/fileexchange/5616-generalized-hypergeometric-function
Additionally, the following MATLAB Answer threads also provide details on implementing a Hypergeometric function in MATLAB.
- https://www.mathworks.com/matlabcentral/answers/570436-regularized-hypergeometric-function-1f2-within-matlab
- https://www.mathworks.com/matlabcentral/answers/91324-regularized-hypergeometric-function-and-hypergeometric-function-syntax
Hope this helps!
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