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Remove column based on row value

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Jonathan Lam
Jonathan Lam 2024-7-3
评论： Taylor 2024-7-3
Hello all,
A bit new to MATLAB but I have a matrix M that is [2x19]. In the first row are x-values derived from another function, but I want to return a new matrix that excludes the columns in M with an x-value larger than 4 in this case
100 0.909090909090909 1 1.01010101010101 1.13636363636364 1.29870129870130 1.50000000000000 1.51515151515152 1.81818181818182 2 2.27272727272727 2.50000000000000 3 3.03030303030303 3.50000000000000 4 4.50000000000000 4.54545454545455 5
18 1 0.909090909090909 0.900000000000000 0.800000000000000 0.700000000000000 0.606060606060606 0.600000000000000 0.500000000000000 0.454545454545455 0.400000000000000 0.363636363636364 0.303030303030303 0.300000000000000 0.259740259740260 0.227272727272727 0.202020202020202 0.200000000000000 0.181818181818182
I know it might seem like a simple question but I can't seem to use the M = M(M(1,:)<=4, M(:,1) nonmenclature correctly. Would appreciate any help

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采纳的回答

Taylor
Taylor 2024-7-3
Ran in:
A = [1 2 5; 3 4 6; 2 8 9]
A = 3x3
1 2 5 3 4 6 2 8 9
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colsToKeep = ~any(A > 4, 1)
colsToKeep = 1x3 logical array
1 0 0
B = A(:, colsToKeep)
B = 3x1
1 3 2
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  2 个评论
Jonathan Lam
Jonathan Lam 2024-7-3
Thanks so much, I was able to get it with your help.
Taylor
Taylor 2024-7-3
Great! You were on the right track with the logical indexing. any and all are quite useful functions when performing logical indexing.

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