how to draw line from first element of cell array to same cell array but fliplr first element and soon

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how to take the first element from two cell array in single for loop
  2 个评论
Star Strider
Star Strider 2015-4-26
NOTE: This was not the original question (so those of us who Answered it are not as delusional as it might seem from reading our Answers).
The new question is correctly (and more understandably) stated in: how to draw a line from one plotted node to another ploted node.

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采纳的回答

Star Strider
Star Strider 2015-4-26
编辑:Star Strider 2015-4-26
This is the easiest way to do what I believe you want:
CHM = {[] [] [17] [] [6,11] [1 9]};
A = CHM(cellfun(@(x) ~isempty(x), CHM));
A{:} % Display Contents Of ‘A’
produces:
ans =
17
ans =
6 11
ans =
1 9
EDIT: Added results of displaying ‘A’
  9 个评论
singh
singh 2015-4-27
ok star and dpb, forget last query suppose star give me solution
A = CHM(cellfun(@(x) ~isempty(x), CHM));
A{:} % Display Contents Of ‘A
B=fliplr(A) % Display Contents Of ‘B
now how to assign two different variable (C and D) values from two cells array A and B until both array will be end and plz used all in the single loop except A and B used in the loop
suppose variable C has first value of A and D has first value of B
now variable C has second value of A and D has second value of B
so on
dpb
dpb 2015-4-27
After the above (SS's solution) for A then it's simply
A=[A(:)]; % convert A cell array to row vector, NB: SS leaves as cell
B=fliplr(A); % now reverse for B
C=A; % make two copies (or assign C, D instead of A,B above)
D=B;

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更多回答(1 个)

dpb
dpb 2015-4-26
编辑:dpb 2015-4-26
>> CHM={[];[];17;[];[6 11];[1 9]};
>> for i=1:length(CHM)
if ~isempty(CHM{i}) % NB "the curlies" {} in the addressing...
disp([num2str(i) ': ' num2str(CHM{i})])
end
end
3: 17
5: 6 11
6: 1 9
>>

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