how to access cell array data with single for loop

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singh
singh 2015-4-27
回答： Thorsten 2015-4-27
A={1;{2,3};{4,5}} %cell array
B={11,12);{13,14};15} %cell array
C = cell( size(A));
D = cell( size(B));
for ii=1:length(A)
C(ii) = A(ii);
D(ii) = B(ii);
end
i wish to use only one for loop and i get output from this code is
when iteration ii =1 then
C=1
D=11
iteartion ii=2 then
C=2
D=12
iteratioin ii=3 then
C=3
D=13
iteration ii=4 then
C=4
D=14
iteartion ii=5
C=5
D=15
i need only one for loop whole process
  1 个评论
Guillaume
Guillaume 2015-4-27
Why do you want to use a loop in the first place? Assuming A and B are the same size, your code is the same as
C = A;
D = B;
If A and B are not the same size, in particular if the largest dimension of A is greater than the number of elements in B, then your code will error, since you use the A dimension to access the B dimension.
Finally, I wouldn't use length. I would use numel for vectors.

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回答（1 个）

Thorsten
Thorsten 2015-4-27
C = flatten(A);
D = flatten(B);
using my function
function [y, me] = flatten(x)
%FLATTEN Flatten numeric data (ND matrices or arbitrarily nested cells)
%
% [Y, ME] = FLATTEN(X)
%
%Sample usage:
% A={1; {2,3}; {4,5}; {6,{7,8}}}
% flatten(A)
%
% Thorsten.Hansen@psychol.uni-giessen.de 2015-04-27
if ~iscell(x)
y = x(:);
else
y = [];
for i = 1:numel(x)
try
xi = cell2mat(x{i});
catch me
xi = flatten(x{i});
end
y(end+1:end+numel(xi)) = xi;
end
end

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