why does this line of code give error- disp("The density of " + element ... + "is" + density). When i press the 'enter ' key after the 3 dots and rerun, it works.
30 次查看(过去 30 天)
显示 更早的评论
if doPlot == 1
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp("The Density of " + element ... + "is" + density)
end
0 个评论
采纳的回答
Shivansh
2024-8-18,13:46
Hello funmilayo,
The error you're encountering is due to the way MATLAB handles line continuations. In MATLAB, the symbol (...) is used to indicate that a statement continues on the next line. However, if you press the 'Enter' key after the ellipsis, it correctly interprets the continuation.
You can modify your code as shown below to avoid the error:
if doPlot == 1
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp("The Density of " + element ...
+ " is " + density)
end
I hope it resolves the query!
更多回答(1 个)
John D'Errico
2024-8-18,13:54
编辑:John D'Errico
2024-8-18,13:59
Do this instead:
disp("The Density of " + element + " is " + density)
What did you write?
disp("The Density of " + element ... + "is" + density)
This must fail, because you stuffed that ... line continuation flag in there. But you did not actually split the line of code onto a second line. That confuses MATLAB. Do you see the second half of the line is green? That tells you MATLAB apparently thinks that second part of the line after the ellipsis is a comment. And now it thinks the line is incomplete, that a closing parens is missing, etc. Remember: anything in green was interpreted as a comment.
If you wanted to put the ellipsis inside quotes, to be displayed, that would work. But computers are very easily confused.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!