Employing RegularizeData3D function

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Roderick
Roderick 2024-9-3
回答： Yash 2024-9-3
Dear all
I have a one-dimensional array, let's call it z, which has a given value for each pair of points (x,y). Let's say that x ranges from 0 to 300 and y from 0 to 50, being both 1D arrays too. Now, I am interested in rearrange the data to plot it through imagesc. At the same time, I want to increase the density of values of z within the spatial domain given by the 2D minimum and maximal values of x and y, respectively.
For that, I am using the RegularizeData3D function as follows:
new_x=linspace(min(x),max(x),1000);
new_y=linspace(min(x),max(y),500);
new_z=RegularizeData3D(x,y,z,new_x,new_y,'interp','bicubic','smoothness',1e-4);
However, it seems that new_z has 500x1000 dimensions, so I am not sure about which should be the order of the inputs to RegularizeData3D to a 1000x500 array, so that the each column represents each value of new_x and each row each value of new_y.

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回答（1 个）

Yash
Yash 2024-9-3
Hello Richard,
I couldn't find detailed documentation for the "RegularizeData3D" function you mentioned. The Add-On page does not specify the output dimensions. However, after reviewing the function code and its behavior, it seems that the output size is xnodes * ynodes, where "xnodes" corresponds to "new_x" and "ynodes" corresponds to "new_y" in your query.
You should avoid directly swapping "new_x" and "new_y" in the code, as this might lead to incorrect output because "new_x" and "x" are related and "new_y" and "y" are related. If you need to adjust the output dimensions, consider transposing the output "new_z" to achieve the desired size.
For more information on how to transpose matrices in MATLAB, you can refer to the following documentation: https://www.mathworks.com/help/matlab/ref/transpose.html
I hope this helps!

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