How can I find the maximum element of each column of a cell array
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I have a cell array like this:
if true
ca={'x' 1 1 9 3;'y' 5 1 1 1; 'z' 5 7 5 9};
end
I have to find the max number of each column then divide all element of that column to maximum I wrote this code but it had errors:
if true
for j=2:3
max_column=max(ca(:,j));
for i=1:5
ca(i,j)= ca(i,j)/max_column;
end
end
disp(ca)
end
Please help me to edit this code. thanks in advance
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采纳的回答
Gopalkrishna Bhat
2015-5-5
Hi Afsane,
The first column of char elements have to be removed & then the cell needs to converted to a matrix. Then you can run the code.
ba={'x' 1 1 9 3;'y' 5 1 1 1; 'z' 5 7 5 9};
temp = [ba(:,2),ba(:,3),ba(:,4),ba(:,5)];
ca = cell2mat(temp)
for j=1:4
max_column=max(ca(:,j));
for i=1:3
ca(i,j)= ca(i,j)/max_column;
end
end disp(ca)
7 个评论
Guillaume
2015-5-5
No, I mean:
ca(:, 2:end) = num2cell(ba);
for loops are often unnecessary in matlab. You can operate on the whole matrix / cell array at once.
更多回答(1 个)
Jos (10584)
2015-5-5
Life would be much easier if you didn't have your data arranges like this in the first place. How did you get this cell array? I strongly suggest you reconsider your approach.
1 个评论
Stephen23
2015-5-6
编辑:Stephen23
2015-5-6
Yes!
Strangely it seems to be the people with the most awkward and bizarre nested data arrangements that insist that "this is the only way" to arrange it, and that "it has to be this way..."... usually followed up with some painful loops and a whole brace [sic] of braces, parentheses and brackets...
Sigh
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