How can I create a sub-matrix if the number of rows change according to main-matrix?
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% I have 9x1 sized A matrix as below:
A=[2.36; 2.36; 2.36; 1.93; 1.93; 1.41; 1.41; 1.41; 0.39]
% from 3rd row to 4th row
% from 5th row to 6th row
% from 8th row to 9th row, values of rows change
% I wanna have B=[4;6;9]. it is just an example! I wanna have a general code including the value changes based on from ith row to jth row...In the end B matrix could be like B= [j;...;....] (maybe 15x1 sized matrix)
P.S : The number of columns is always "1"
% How can I solve that problem? Many Thanks!
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回答(2 个)
Andrei Bobrov
2015-5-6
编辑:Andrei Bobrov
2015-5-6
A=[2.36; 2.36; 2.36; 1.93; 1.93; 1.41; 1.41; 1.41; 0.39];
[a,b,c] = unique(A,'first');
[ignored,ii] = sort(b);
b1 = b(ii);
a1 = a(ii);
B = b1(2:end);
out = diff(a1);
or
D = diff(A(:));
B = find([false;D~=0]);
out = D(B - 1);
2 个评论
Purushottama Rao
2015-5-6
@Andrei: Sir,I tried your code and got the following error meesage
A=[2.36; 2.36; 2.36; 1.93; 1.93; 1.41; 1.41; 1.41; 0.39]; [a,b,c] = unique(A,'first'); [~,ii] = sort(b); b1 = b(ii); a1 = a(ii); B = b1(2:end); out = diff(a1); ??? [~,ii] = sort(b); | Error: Expression or statement is incorrect--possibly unbalanced (, {, or [.
what was that
Purushottama Rao
2015-5-6
clc
k=0;
for i=2:(length(A))
if (A(i)~=A(i-1))
k=k+1
b(k)=i
end
end
Try out this..
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