plot bar graph based on element type in matrix

Question

Kitt 2024-10-7

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2158030-plot-bar-graph-based-on-element-type-in-matrix

评论： Star Strider 2024-10-7

I have a 20x100 (t,N) matrix with each element being either 1, 2, or 3. I want to create a bar graph showing the amount of each type of element. so at t=20, of the 100 columns, how many have 1, how many have 2, how many have 3.

Is that possible?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Star Strider 2024-10-7

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2158030-plot-bar-graph-based-on-element-type-in-matrix#answer_1528265

编辑：Star Strider 2024-10-7

在 MATLAB Online 中打开

Do you want all of them, or just the last row (t=10)?

This does both —

A = randi(3, 20, 100)

A = 20×100

2 2 1 3 1 3 3 3 1 1 1 2 2 2 1 3 3 1 1 1 2 3 3 1 2 1 2 1 2 1 2 2 3 3 1 1 3 3 3 2 3 1 1 3 2 1 1 1 2 2 1 2 1 1 3 2 3 3 3 2 3 2 3 2 2 1 3 1 2 3 3 3 3 2 2 2 1 1 2 3 2 2 3 1 1 1 1 1 1 1 2 1 3 3 3 1 1 1 3 1 3 1 2 1 1 1 1 1 1 3 1 2 2 3 3 1 3 1 1 1 2 3 3 1 3 2 1 3 1 2 3 1 2 2 1 1 1 1 2 3 1 1 1 3 2 3 1 2 3 3 1 2 2 2 2 2 1 3 2 3 3 3 3 2 2 2 3 3 2 2 3 1 2 1 1 2 3 1 1 2 3 1 2 3 2 2 3 2 3 2 2 1 1 2 3 1 3 3 1 3 2 1 3 1 1 1 3 3 2 1 1 2 2 3 1 3 1 1 3 2 3 3 3 1 3 2 1 3 3 1 3 2 2 3 3 2 2 3 1 3 1 3 1 2 2 3 2 1 3 1 2 2 2 1 1 2 2 3 2 1 1 3 3 3 1 2 3 1 3 1 1 1 3 1 2 1 1 3 2 2 3 3 2 3 2 3 1 2 1 3 1 2 1 2 1 2 1 1 2 3

<mw-icon class=""></mw-icon>

TallyAll = accumarray(A(:), 1)

TallyAll = 3×1

675 645 680

ResultAll = table(TallyAll, 'RowNames',compose('%d',1:3))

ResultAll = 3x1 table

TallyAll ________ 1 675 2 645 3 680

figure

bar(1:3, TallyAll)

Tally20 = accumarray(A(20,:).', 1)

Tally20 = 3×1

35 30 35

Result20 = table(Tally20, 'RowNames',compose('%d',1:3))

Result20 = 3x1 table

Tally20 _______ 1 35 2 30 3 35

figure

bar(1:3, Tally20)

EDIT — Forgot about the bar plots. Now added.

.

8 个评论
显示 6更早的评论隐藏 6更早的评论

Star Strider 2024-10-7

在 MATLAB Online 中打开

O.K. That was not initially obvious.

Two options —

A = randi(3, 20, 100)

A = 20×100

3 1 3 1 2 1 2 3 3 3 2 1 1 2 2 1 2 2 3 2 1 3 2 3 2 2 2 3 2 2 3 1 2 3 2 1 2 3 1 3 2 3 2 2 3 2 2 3 1 2 3 1 2 2 3 3 1 1 1 3 1 3 2 2 2 2 1 1 3 1 2 1 2 2 1 2 1 2 2 2 2 2 3 1 3 1 3 3 1 2 1 1 1 3 3 3 1 2 3 1 3 1 1 1 1 3 1 3 1 3 1 3 1 3 1 3 1 1 2 3 2 3 3 3 1 1 1 3 1 2 2 3 1 2 2 1 1 2 1 2 2 2 2 2 2 2 2 2 1 2 1 1 2 1 2 3 3 2 2 3 3 3 1 2 2 2 1 2 3 2 3 1 1 2 3 2 2 3 3 2 2 3 3 3 1 1 2 2 3 3 3 1 1 2 2 1 2 1 1 1 1 1 2 3 1 1 2 2 3 1 2 1 3 2 3 3 3 2 1 3 2 3 2 2 3 1 2 3 2 1 3 2 2 2 3 2 3 3 2 2 2 1 2 1 1 3 3 3 1 3 3 3 1 2 1 1 3 2 3 1 3 2 1 3 3 1 1 1 3 3 1 2 3 3 1 3 3 2 1 3 3 3 2 3 3 1 2 1 3 1 2 3 1 2 3 2 2 1 1 1

<mw-icon class=""></mw-icon>

for k = 1:size(A,1)

Tally(:,k) = accumarray(A(k,:).', 1);

end

figure

tiledlayout(5,4, TileIndexing='columnmajor')

for k = 1:size(Tally,2)

nexttile

bar(1:3, Tally(:,k))

grid

title("Row "+k)

end

figure

bar3(1:3, Tally)

xlabel('Rows')

ylabel('Responses')

The first option presents each result in a separate plot, the second option presents all of them in a single 3D plot.

.

Star Strider 2024-10-7

在 MATLAB Online 中打开

No worries.

Your ‘optchosen’ variable needs to be a (20x100) matrix with all three choices present in each row to work wiith my original code. There may be only two choices in some rows, and that would definitely not work with my code, since it depends on every row having all three choices.

One possibiility is to preallocate the ‘Tally’ matrix, and additionally be certain that the choices are allocated correctly in each column —

A = randi(3, 20, 100)

A = 20×100

2 2 1 1 3 3 3 2 2 1 2 1 1 3 3 3 3 3 2 3 3 3 1 1 2 1 3 1 2 3 3 2 1 2 2 3 1 3 1 1 1 1 2 1 3 2 3 1 1 2 3 3 1 3 2 1 2 1 3 1 2 1 1 1 3 2 3 2 3 3 1 2 1 1 3 2 3 3 1 3 2 3 2 3 2 2 1 2 3 2 3 3 1 3 3 1 1 2 3 1 3 2 1 2 3 3 1 1 2 1 2 3 2 2 3 1 2 3 1 3 1 2 3 1 3 1 2 2 3 2 1 3 3 3 3 3 1 2 1 2 3 3 2 1 3 3 2 1 2 2 2 1 1 2 1 3 1 3 2 1 1 3 2 3 1 2 2 3 2 2 2 2 1 2 3 1 3 2 2 3 2 1 1 3 2 1 1 2 1 2 3 3 2 2 1 1 1 2 3 3 3 3 2 3 2 1 1 2 2 3 2 2 1 3 2 3 3 3 1 1 2 1 2 1 3 1 3 1 3 1 1 1 2 2 1 1 3 2 3 3 1 1 3 1 3 1 3 3 2 1 3 2 2 3 3 2 2 1 2 3 3 3 3 2 3 3 2 2 3 3 3 1 3 1 1 1 3 3 3 3 2 3 3 2 3 3 3 3 3 3 1 3 3 1 3 2 1 2 3 3

<mw-icon class=""></mw-icon>

A(5,:) = randi(2, 1, 100); % Test #1 (No 3’s)

A(10,:) = randi([2 3], 1, 100); % Test #2 (No 1’s)

A(15,A(15,:) == 2) = 3; % Test #3 (No 2’s)

Tally = zeros(3, size(A,1));

for k = 1:size(A,1)

Uchoice = unique(A(k,:));

Count = accumarray(A(k,:).', 1); % Raw Count Veector

Tally(Uchoice,k) = Count(Count ~= 0); % Allocate ‘Tally’ Results To Non-Zero Rows

end

figure

tiledlayout(5,4, TileIndexing='columnmajor')

for k = 1:size(Tally,2)

nexttile

bar(1:3, Tally(:,k))

grid

title("Row "+k)

end

figure

bar3(1:3, Tally)

xlabel('Rows')

ylabel('Responses')

That should allocate the choices correctly, and be certain that every column has three rows, even if some contain zero counts. (This worked when I tested it.)

.

Kitt 2024-10-7

That worked PERFECTLY haha!!

Thank you so much!

Star Strider 2024-10-7

As always, my pleasure!

请先登录，再进行评论。

Answer 2

dpb 2024-10-7

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2158030-plot-bar-graph-based-on-element-type-in-matrix#answer_1528270

在 MATLAB Online 中打开

M=randi([1 3],20,100);

whos t

[min(M(:)) max(M(:))]

ans = 1×2

1 3

histogram(M(20,:))

xticks(1:3)

xlabel('Bin'), ylabel('Count')

title('Counts for t=20')

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Kitt 2024-10-7

I've tried the histogram but the problem is I want to see the distribution over time, and when I try to plot multiple histograms they are just on top of each other and I can't really see the change

请先登录，再进行评论。

plot bar graph based on element type in matrix

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

采纳的回答

8 个评论
显示 6更早的评论隐藏 6更早的评论

更多回答（1 个）

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

另请参阅

类别

标签

Community Treasure Hunt

plot bar graph based on element type in matrix

0 个评论 显示 -2更早的评论隐藏 -2更早的评论

采纳的回答

8 个评论 显示 6更早的评论隐藏 6更早的评论

更多回答（1 个）

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

另请参阅

类别

标签

Community Treasure Hunt

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

8 个评论
显示 6更早的评论隐藏 6更早的评论

1 个评论
显示 -1更早的评论隐藏 -1更早的评论