A question about the declaration of public properties in apps

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Muazma Ali
Muazma Ali 2024-10-12
评论： Steven Lord 2024-10-12
Hi! :)
I have a question: if I have declared a property as a public variable in my main app, is it necessary that I also declare it as a private property in the app I am using it.
In my case I have a table Osmotisk_data that I have declared as a public property in the main app, then I am using some of the columns (arrays) from this table in another app, there I have declared it as a private property, but I am a little confused becuase I am not getting the results that I am supposed to get.

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回答（1 个）

Steven Lord
Steven Lord 2024-10-12
How are you planning to share the data between the two apps? This documentation page offers some guidance on how to do that.
  2 个评论
Muazma Ali
Muazma Ali 2024-10-12
I didn't understand your question: isnt the data automatically shared when I declare the variable as public in the main app..?
Steven Lord
Steven Lord 2024-10-12
Ran in:
Anyone with access to the app object has access to its public properties. But are you giving that second app access to that first app object?
As a non-app example, I'll create a variable R. Don't worry too much about the details of what it is. What's important is that it's an object.
R = RandStream.create('mt19937ar');
It has properties that I can get since I have access to the object.
p = properties(R)
p = 9x1 cell array
{'Type' } {'Seed' } {'NumStreams' } {'StreamIndex' } {'State' } {'Substream' } {'NormalTransform'} {'Antithetic' } {'FullPrecision' }
S = R.Seed
S = uint32 0
But if I call a function and don't give it the object, it can't ask for properties of the object even though they're public. It has no idea what R is, even though it exists in the calling workspace. It didn't get passed into the myfun workspace.
myfun() % will error, doesn't know what R is
Inside function myfun, trying to get the Seed property from R
Unable to resolve the name 'R.Seed'.

Error in solution>myfun (line 7)
y = R.Seed; % will error
function myfun
disp("Inside function myfun, trying to get the Seed property from R")
y = R.Seed; % will error
end
That documentation page I linked to gives some guidance about how to make the first app object accessible to the second app.

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