Concatenating multiple struct fields into a single matrix or array but maintaining dimensions

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Vyte Jan
Vyte Jan 2024-10-14
评论： Voss 2024-10-15
Hi,
I've got a struct question. I have read a lot of similar questions & answers online, but its just not what I am trying to do.
I have struct: s=A.B.C and in location C I have a 100 fields with different string names (ie name01, name02..). Each array is 128x57 of numbers.
I want to concatinate these arrays into one single matrix of 12800 x 57 (maintaining the two dimensions).
-if possible- I'd like to know how to concatinate 'everything' in s=A.B.C location. Although, I would be interested to know how I could do a for loop to pass through a list of string names (name01, name02...) as something more advanced.
I have tried cellfun but it concatinated all the values into 1 dimension. I think I'm missing something very small.
I have added a screenshot of what C location displays.
Thanks!
V

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采纳的回答

Voss
Voss 2024-10-14
Ran in:
For demonstration, first I create a similar struct, with 3 fields in A.B.C:
N = 3;
args = [compose('name%02d',1:N); permute(num2cell(rand(128,57,N),[1 2]),[1 3 2])];
A = struct('B',struct('C',struct(args{:})));
A.B.C
ans = struct with fields:
name01: [128x57 double] name02: [128x57 double] name03: [128x57 double]
Make a cell array containing the contents of all fields of A.B.C:
tmp = struct2cell(A.B.C)
tmp = 3x1 cell array
{128x57 double} {128x57 double} {128x57 double}
To concatenate the contents of all fields of A.B.C together into a matrix:
result = vertcat(tmp{:})
result = 384×57
0.7016 0.5247 0.4862 0.8103 0.5211 0.8613 0.8348 0.7944 0.3241 0.1879 0.8924 0.2318 0.1042 0.6421 0.8176 0.1636 0.1577 0.1961 0.6061 0.0339 0.3641 0.5759 0.2847 0.1911 0.2540 0.1149 0.6864 0.2224 0.7385 0.3767 0.2621 0.3619 0.7734 0.0089 0.0116 0.5627 0.5977 0.8290 0.0089 0.6186 0.7530 0.1505 0.2660 0.8529 0.7806 0.5531 0.3912 0.0874 0.8604 0.3982 0.0738 0.9015 0.5513 0.8662 0.4306 0.3957 0.7498 0.2443 0.3472 0.2054 0.5630 0.0517 0.8014 0.5588 0.0532 0.7560 0.9364 0.2610 0.0868 0.3247 0.6822 0.5275 0.3303 0.8314 0.1889 0.9540 0.1451 0.9704 0.2671 0.7753 0.4977 0.5302 0.9841 0.7130 0.0383 0.8599 0.6455 0.9030 0.9149 0.2388 0.5687 0.9936 0.0542 0.8198 0.9997 0.2423 0.3567 0.8020 0.9059 0.7126 0.5800 0.6057 0.1721 0.4625 0.0752 0.1642 0.1244 0.2837 0.7200 0.2966 0.9713 0.6430 0.8155 0.3751 0.5341 0.8163 0.2921 0.8052 0.5792 0.9894 0.0475 0.1832 0.5740 0.0422 0.4658 0.4820 0.5843 0.0125 0.6813 0.0260 0.7554 0.1029 0.7144 0.7884 0.0089 0.0718 0.3100 0.2234 0.9659 0.1897 0.6523 0.9967 0.2368 0.2868 0.4206 0.5245 0.2047 0.4164 0.4774 0.1258 0.5088 0.8898 0.1491 0.7946 0.3345 0.3264 0.3214 0.6803 0.9500 0.6012 0.5480 0.4982 0.0083 0.9412 0.8471 0.2508 0.6779 0.2592 0.0837 0.7914 0.2430 0.9371 0.0049 0.7605 0.9514 0.1945 0.3468 0.2530 0.1946 0.0056 0.7659 0.3749 0.0376 0.5007 0.0392 0.4582 0.9460 0.3561 0.9162 0.0650 0.4116 0.5289 0.7467 0.1570 0.0253 0.1596 0.2651 0.3299 0.1725 0.1516 0.4624 0.8052 0.4739 0.5744 0.6836 0.6825 0.2760 0.1197 0.9845 0.5648 0.9507 0.1311 0.8476 0.1509 0.3859 0.1826 0.7287 0.0391 0.4908 0.7467 0.7834 0.7271 0.1525 0.4270 0.5421 0.5615 0.5153 0.3698 0.9105 0.9994 0.5853 0.7787 0.2159 0.0872 0.9116 0.3400 0.3118 0.5427 0.5982 0.5155 0.0619 0.2524 0.2880 0.4094 0.9142 0.3345 0.5506 0.1278 0.3061 0.9158 0.3516 0.5175 0.0004 0.7909 0.1788 0.2399 0.9074 0.6564 0.3081 0.0641 0.9159 0.5541 0.1051 0.8818 0.5873 0.8778 0.7733 0.2257 0.7580 0.8650 0.8074 0.2022 0.5826 0.4097 0.7341 0.2222 0.5092 0.6195 0.5186 0.7212 0.1556 0.7701 0.5459 0.9372 0.2567 0.9235 0.8696 0.6289 0.2800 0.4231 0.0879 0.7028 0.3715 0.3526 0.5253 0.8801 0.1735 0.0905 0.2753 0.0422
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To concatenate the contents of only certain fields of A.B.C together:
idx = ismember(fieldnames(A.B.C),{'name01','name03'}); % taking name01 and name03 only, for example
result = vertcat(tmp{idx})
result = 256×57
0.7016 0.5247 0.4862 0.8103 0.5211 0.8613 0.8348 0.7944 0.3241 0.1879 0.8924 0.2318 0.1042 0.6421 0.8176 0.1636 0.1577 0.1961 0.6061 0.0339 0.3641 0.5759 0.2847 0.1911 0.2540 0.1149 0.6864 0.2224 0.7385 0.3767 0.2621 0.3619 0.7734 0.0089 0.0116 0.5627 0.5977 0.8290 0.0089 0.6186 0.7530 0.1505 0.2660 0.8529 0.7806 0.5531 0.3912 0.0874 0.8604 0.3982 0.0738 0.9015 0.5513 0.8662 0.4306 0.3957 0.7498 0.2443 0.3472 0.2054 0.5630 0.0517 0.8014 0.5588 0.0532 0.7560 0.9364 0.2610 0.0868 0.3247 0.6822 0.5275 0.3303 0.8314 0.1889 0.9540 0.1451 0.9704 0.2671 0.7753 0.4977 0.5302 0.9841 0.7130 0.0383 0.8599 0.6455 0.9030 0.9149 0.2388 0.5687 0.9936 0.0542 0.8198 0.9997 0.2423 0.3567 0.8020 0.9059 0.7126 0.5800 0.6057 0.1721 0.4625 0.0752 0.1642 0.1244 0.2837 0.7200 0.2966 0.9713 0.6430 0.8155 0.3751 0.5341 0.8163 0.2921 0.8052 0.5792 0.9894 0.0475 0.1832 0.5740 0.0422 0.4658 0.4820 0.5843 0.0125 0.6813 0.0260 0.7554 0.1029 0.7144 0.7884 0.0089 0.0718 0.3100 0.2234 0.9659 0.1897 0.6523 0.9967 0.2368 0.2868 0.4206 0.5245 0.2047 0.4164 0.4774 0.1258 0.5088 0.8898 0.1491 0.7946 0.3345 0.3264 0.3214 0.6803 0.9500 0.6012 0.5480 0.4982 0.0083 0.9412 0.8471 0.2508 0.6779 0.2592 0.0837 0.7914 0.2430 0.9371 0.0049 0.7605 0.9514 0.1945 0.3468 0.2530 0.1946 0.0056 0.7659 0.3749 0.0376 0.5007 0.0392 0.4582 0.9460 0.3561 0.9162 0.0650 0.4116 0.5289 0.7467 0.1570 0.0253 0.1596 0.2651 0.3299 0.1725 0.1516 0.4624 0.8052 0.4739 0.5744 0.6836 0.6825 0.2760 0.1197 0.9845 0.5648 0.9507 0.1311 0.8476 0.1509 0.3859 0.1826 0.7287 0.0391 0.4908 0.7467 0.7834 0.7271 0.1525 0.4270 0.5421 0.5615 0.5153 0.3698 0.9105 0.9994 0.5853 0.7787 0.2159 0.0872 0.9116 0.3400 0.3118 0.5427 0.5982 0.5155 0.0619 0.2524 0.2880 0.4094 0.9142 0.3345 0.5506 0.1278 0.3061 0.9158 0.3516 0.5175 0.0004 0.7909 0.1788 0.2399 0.9074 0.6564 0.3081 0.0641 0.9159 0.5541 0.1051 0.8818 0.5873 0.8778 0.7733 0.2257 0.7580 0.8650 0.8074 0.2022 0.5826 0.4097 0.7341 0.2222 0.5092 0.6195 0.5186 0.7212 0.1556 0.7701 0.5459 0.9372 0.2567 0.9235 0.8696 0.6289 0.2800 0.4231 0.0879 0.7028 0.3715 0.3526 0.5253 0.8801 0.1735 0.0905 0.2753 0.0422
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  2 个评论
Vyte Jan
Vyte Jan 2024-10-14
Hi @Voss
Amazing! exactly what I needed:)
Just wondering - for the second part (To concatenate the contents of only certain fields of A.B.C together)
I tried to extract the filenames and substitute it, but that didnt work:
names=fieldnames(A.B.C)
idx = ismember(fieldnames(A.B.C),{names})
The 'names' are 100x1 cell. I also tried converting 'names' into a string but that didn't work. Is it possible to convert a column of strings/characters into a single row and substitute it into the line of code?
Thank you!
V
Voss
Voss 2024-10-15
You're welcome!
You'd have to specify some condition on which fields you want to use. In the example, I hard-coded name01 and name03, but you can use any condition that generates a logical vector idx the same length as the number of fields.

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