3D histogram of RGB image

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John Andrew 2015-5-10

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https://ww2.mathworks.cn/matlabcentral/answers/216064-3d-histogram-of-rgb-image

评论： Image Analyst 2017-9-11

11225655_462119083942470_1089232078_n.jpg

Hey guys! I'm performing the 3D histogram of RGB image my teacher said me there is a simple and faster way to do all what I'm doing with my code. But I do not find any reference that help me to achieve that.

I want to obtain the image attached. Does anyone knows how?

Thanks!!

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Image Analyst 2015-5-11

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https://ww2.mathworks.cn/matlabcentral/answers/216064-3d-histogram-of-rgb-image#answer_178689

color_gamut_visualizer.m

I just don't see how hist3 can do it. Despite it's poor choice of a name (in my opinion), it's really a 2D histogram, not a 3D histogram because there are only 2 independent variables. Try my color gamut visualizer program, attached way below, below all the images.

It's a primitive MATLAB version of the really nice one that is an ImageJ plugin.

The imageJ plugin is here: http://rsb.info.nih.gov/ij/plugins/color-inspector.html

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salma samiei 2017-9-11

Actually, your answer is related to "gamut3D(rIndex, gIndex, bIndex) = gamut3D(rIndex, gIndex, bIndex) + 1;" part. but I am asking why we plus the value of channels with one?! for example, if the value of red channel in row 2, column 1 = 128 we add it with 1 and save 129 in rindex. I hope my question be clear now?

Image Analyst 2017-9-11

Because indexes can't be zero, but gray levels can. You can't have indexes in the range 0-255, but you can in the range 1-256 so that's why 1 is added to the index.

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