Are there alternative ways to write codes to calculate a_p ?

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Here
given
m= 0:n+1
n is the degree of Bspline which can be any value
p = 0:n
k=k0:k1;
k0 =ceil(d-((n+1)/2));
k1 =floor(d+((n+1)/2));
num_points = 1; % Change this if you need more points
% Generate random variable d uniformly in the range (-0.5, 0.5)
d = -0.5 + (0.5 - (-0.5)) * rand(num_points, 1);
mu is the unit step function or heaviside function
I tried to develop the function a_P
function a_p = calculate_ap(n, d)
% n: Degree of the polynomial
% d: Interpolation point as a random variable with |d| < 0.5
% Define the range for p (0 to n)
p_values = 0:n;
% Calculate the lower and upper bounds of k
k0 = ceil(d - (n + 1) / 2);
k1 = floor(d + (n + 1) / 2);
% Define the range for k
k_values = k0:k1;
% Initialize a matrix to store a_p(k) values
a_p = zeros(length(p_values), length(k_values));
% Loop through each value of p to compute a_p for each k
for p_idx = 1:length(p_values)
p = p_values(p_idx);
% Calculate the binomial coefficient (n choose p)
binomial_np = nchoosek(n, p);
% Calculate the factorial term 1/n!
n_factorial_term = 1 / factorial(n);
% Loop through each value of k
for k_idx = 1:length(k_values)
k = k_values(k_idx);
% Initialize the sum for this combination of p and k
sum_result = 0;
% Sum over m from 0 to n+1
for m = 0:n+1
% Calculate the binomial coefficient (n+1 choose m)
binomial_n1m = nchoosek(n+1, m);
% Calculate the term (-1)^m
sign_term = (-1)^m;
% Calculate the term (n+1)/2 - m
difference_term = (n+1) / 2 - m;
% Calculate the term (difference_term)^(n-p)
power_term = difference_term^(n - p);
% Calculate the Heaviside function mu(p - m + (n+1)/2)
mu_term = heaviside(p - m + (n+1)/2);
% Add the current term to the sum
sum_result = sum_result + binomial_n1m * sign_term * power_term * mu_term;
end
% Calculate a_p(k) for the current p and k
a_p(p_idx, k_idx) = n_factorial_term * binomial_np * sum_result;
end
end
For solving this function
n= input("Enter the degree:"); %Degree
p=0:n;
a_p = calculate_ap(n,p);
disp(a_p)
solution is :
for n= 3
0.6667 0.6667 0.6667 0.6667 0.6667
-1.0000 -1.0000 -1.0000 -1.0000 -1.0000
0.5000 0.5000 0.5000 0.5000 0.5000
0 0 0 0 0
>> Is this function written correctly does it need any change ? Please could you suggest?

回答(1 个)

Subhajyoti
Subhajyoti 2024-10-23,15:58
You can try precomputing values and vectorized operations to efficiently calculate the given equation. Additionally, dynamic programming paradigm helps in avoiding repeated calculations and optimizes code efficiency.
Here, in the following implementation, I have utilized precomputed factorial and binomials to compute the equation.
MAX_N = 10000;
% preallocate memory for factorial values upto MAX_N
factorial_values = cumprod(1:MAX_N);
function y = fact(n)
global MAX_N, factorial_values;
if n==0
y = 1;
else
y = factorial_values(n);
end
end
% preallocate 2-dimentions array to precompute binomial coefficients
binomial_values = zeros(MAX_N, MAX_N);
% precompute binomial coefficients using dynamic programming
for n = 1:MAX_N
for k = 0:n
if k == 0 || k == n
binomial_values(n+1, k+1) = 1;
else
binomial_values(n+1, k+1) = binomial_values(n, k) + binomial_values(n, k+1);
end
end
end
function nCr(n, r)
global binomial_values;
binomial_values(n+1, r+1)
end
function a_p = calculate_ap(n, p)
ans = 0;
for m = 0:n+2
sign_term = (-1)^m;
base = ((n+1)/2 - m);
power_term = (base)^(n-p);
% Calculate the Heaviside function mu(p - m + (n+1)/2)
mu = heaviside(p - m + (n+1)/2);
ans = ans + nCr(n+1, m) * sign_term * power_term * mu;
end
ans = ans / (fact(n-p) * fact(p));
end
For repetitive calculations, you can try to further optimize the code by memorizing the “heaviside” function and utilising binary exponentiation algorithm.
Additionally, you can refer to the following resources to know more about using common techniques used to improve code run-time:
  3 个评论
Rohitashya
Rohitashya 2024-10-23,16:11
MAX_N = 10000;
% preallocate memory for factorial values upto MAX_N
factorial_values = cumprod(1:MAX_N);
function y = fact(n)
global MAX_N, factorial_values;
if n==0
y = 1;
else
y = factorial_values(n);
end
end could you explain this part a bit ?

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