I'm trying to integrate using Simpson's rule

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ray sanchez
ray sanchez 2015-5-13
评论： Walter Roberson 2015-5-14
I'm trying to integrate sin(x) from 0 to pi using the simpson's rule. The only thing is I need it to output several iterations each with a different number of intervals. For example, n= 4, 8 , 16, 32, 64. Here is my code so far clear; close all; clc;
ezplot('sin(x)', [0, pi]), hold on
f=@(x) sin(x);
a=0;b=pi;
n=4;
h=(b-a)/n;
p=0;
for i=a:b
p=p+1;
x(p)=i;
y(p)= sin(i);
plot(x, sin(x), 'r')
end
l=length(x);
x
y
any help appreciated!

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回答（1 个）

Walter Roberson
Walter Roberson 2015-5-13
So instead of "n=4" use
for n = [4, 8, 16, 32, 64]
and put an "end" after.
  2 个评论
ray sanchez
ray sanchez 2015-5-13
Where would I put the "end"? I tried it in several places and it didn't work
Walter Roberson
Walter Roberson 2015-5-14
for n = [4, 8, 16, 32, 64]
h=(b-a)/n;
p=0;
for i=a:b
p=p+1;
x(p)=i;
y(p)= sin(i);
plot(x, sin(x), 'r')
drawnow();
end
l=length(x);
x
y
end
Right at the end.
Note that I also added a drawnow() call so you have a hope of seeing the plots you are generating. I have no idea why you would want to plot in the manner you are plotting, but I guess you must have a reason.

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