INTEGARTION OF BESSELH function

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george veropoulos
george veropoulos about 12 hours 前
移动Steven Lord about 2 hours 前
Hi
i make a code where i integrate the hankel function besselh(0, 2)
function z = Escat(r,phi)
[f,N,ra,k0,Z0] =parameter();
[Is]=currentMoM()
Phim=zeros(N+1);
FINAL=0;
for jj=1:N
%Phi0(jj)=(jj-1).*(pi./N);
Phi0(jj)=(jj-1).*(2.*pi./N);
FINAL=FINAL-(k0.*Z0./4).*Is(jj).*ra.*integral(@(xx)besselh(0,2,k0.*sqrt(ra.^2+r.^2-2.*r.*ra.*(phi-xx))),Phi0(jj),2*pi/N+Phi0(jj));
end
z=FINAL;
end
when i plot the function in the range φ=0 : 2π with r=const the valus of Escat are extremely bih value ...
clear all
clc
[f,N,ra,k0,Z0] = parameter();
%ph_i=pi/2;
rho=10.*ra ;
phi=0:pi/180:2*pi;
Es=zeros(length(phi));
%phi=0:pi/200:pi/3
for jj=1:length(phi)
Es(jj)=abs(Escat(rho,phi(jj)));
end
plot(phi*(180./pi),Es,'b--')
hold on
%plot(phi*(180./pi),abs(integ),'b--')
plot(phi,abs(Escattheory_new(rho,phi)),'r-')
xlabel('$\phi$','Interpreter','latex')
ylabel('$|E_{s}|$','Interpreter','latex' )
%legend('MoM', 'Theory')
hold off
can i check if the the integration is ok ?
the parameter fucntion is
function [f,N,ra,k0,Z0] = parameter()
%UNTITLED Summary of this function goes here
c0=3e8;
Z0=120.*pi;
ra=1;
N=80;
f=300e6;
lambda=c0./f;
k0=2*pi./lambda;
end
thank you
  2 个评论
Steven Lord
Steven Lord about 11 hours 前
You haven't provided two of the functions used by your code: currentMoM and Escattheory_new.
You wrote "the valus of Escat are extremely bih value ..." -- I assume that's a typo and you meant to say "big value". How big is "extremely big" and how big were you expecting the values to be? Why did you expect the values to be so different from the values you actually received?
george veropoulos
george veropoulos about 5 hours 前
移动:Steven Lord about 2 hours 前
thank for your reply
i want to compare the function Escat with Escattheory_new
function y=Escattheory_new(r,phi)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
[f,N,ra,k0,Z0] = parameter();
E0=1;
Z1=k0.*r;
Z2=k0.*ra;
final=0 ;
for kk=0:200
final=final-E0*(besselj(kk,Z2,1).*besselh(kk,2,Z1)./besselh(kk,2,Z2))*(-1j).^kk.*cos(kk.*phi)*e_n(kk);
%z=vpa(symsum(factor,k,0,inf),3)
end
y=final;
end
end the values ar not the same also Near the φ=2*π the Escat take high values 10^16
George

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