I have a 25by3 matrix and i want to remove randomly 10 rows (I have already completed this part). The problem is that i want the original matrix which is 25by3 to be 15by3 after removing 10 rows. Thats my question
显示 更早的评论
Thats my code
X=[x1 x2 x3]; %25by3 matrix
%
k = randperm(size(X,1));
Ex_Ran= X(k(1:10),:)%extract 10 rows randomly
采纳的回答
Star Strider
2015-5-17
Try this:
X=[x1 x2 x3]; %25by3 matrix
k = randperm(size(X,1));
Ex_Ran = X;
Ex_Ran(k(1:10),:) = [] %extract 10 rows randomly
7 个评论
Dennis_Pana
2015-5-17
Star Strider
2015-5-18
This gives you both:
Ex_Rem = X;
Ex_Rem(k(1:10),:) = []; % Remaining Rows
Ex_Ext = X(k(1:10),:); % Extracted Rows
Walter Roberson
2015-5-18
The row numbers of the extracted rows are stored in k(1:10), and the remaining row numbers are stored in k(11:end)
Guillaume
2015-5-18
Note that instead of:
k = randperm(somenumber);
k2 = k(1:n); %only use the first n numbers of k
You can use:
k2 = randperm(somenumber, n); %return n integers picked from 1:somenumber
Walter Roberson
2015-5-18
Originally randperm() did not allow a second argument; it was added a couple of years back. Yesterday a poster ran into the problem of having a release too old to support it.
In the case where, such as here, one wants to also know what was not selected, then the single-argument randperm() is better.
stelios loizidis
2019-8-6
Hello,
I want to tell you that I have the following issue: I am trying to remove 2000 random columns from a matrix A (1653X8000). I applied the above code but Matlab gives me the following error:
Index exceeds the number of array elements (1653)
The code I wrote:
A=[x1 x2, x3.....] %1653by8000 matrix
k=randperm(size(A,1));
B=A;
B(:,k(1:2000))=[];
Your help is valuable!!
Steven Lord
2019-8-6
k is a reordering of the numbers between 1 and the number of rows in A.
You want a reordering of the numbers between 1 and the number of columns in A (which is the size of A in the second dimension) if you want to use it as a set of indices into the columns of B (which starts off as a copy of A.)
更多回答（3 个）
Andrei Bobrov
2015-5-18
n = 10;
m = size(X,1);
out = X(rendperm(m,m-n),:);
Mark Stone
2015-5-18
编辑：Mark Stone
2015-5-18
I show you this just so that you 'll be aware of the very handy setdiff function. it might not be as fast executing as the previous answer, but it is elegant.
X =[x1 x2 x3]; %25by3 matrix
k = randperm(size(X,1));
X = X(setdiff(1:25,k(1:10)),:);
Or you can make the left hand side a new variable, such as Y, if you want to preserve the original 25 by 3 matrix as is.
Y = X(setdiff(1:25,k(1:10)),:);
Murali Krishna
2015-5-18
编辑：Murali Krishna
2015-5-18
0 个投票
To extract 10 rows of a given matrix
a=rand(25,3);%25*3 matrix
b=randperm(10);
c=a([b],:);
k=setdiff(a,c,'rows');
2 个评论
Walter Roberson
2015-5-18
That is going to extract the first 10 rows, but in a random order. You need to randperm() over the whole 25 and take only 10 of the scrambled values as the indices to extract.
Murali Krishna
2015-5-18
Thank u...
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