how to sort histogram generated count and corresponding gray value.. pls help
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m=imread('ll.bmp');
[count,gray]=imhist(m);
the answer is:
i want to sort the count and corresponding gray value..
and delete the zero count values answer like this..
采纳的回答
1 个评论
Image Analyst
2015-5-20
It does the same thing that I did but combined the counts and gray level arrays into a single 2D array (which we didn't know you wanted to do).
更多回答（2 个）
Image Analyst
2015-5-18
Don't use gray as a variable name - it's the name of a built in function that creates a colormap, and you just blew it away.
I don't know why you need to, but to get rid of array elements with zero counts
[count, grayLevels]=imhist(m);
rowsToDelete = count == 0;
count(rowsToDelete) = [];
grayLevels(rowsToDelete) = [];
5 个评论
ARJUN K P
2015-5-18
Image Analyst
2015-5-18
They are already both sorted in terms of increasing gray level. There is a sort() command to use if you want some different kind of sorting, but you should probably take the sort order and apply it to both so that both arrays are always sorted in the same order.
Image Analyst
2015-5-18
To sort in reverse order, simply use fliplr()
count = fliplr(count)
grayLevels = fliplr(grayLevels);
Image Analyst
2015-5-19
% Sort count in descending order.
[sortedCounts, sortIndexes] = sort(count, 'descend');
% Sort grayLevels the same way.
grayLevels = grayLevels(sortIndexes);
ARJUN K P
2015-5-19
0 个投票
sir you mistaken, i want sort the count in decreasing order...
eg:
before sorting
after sorting
i want ans like
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