plotting two-vectors on same axis

3 次查看（过去 30 天）
Raghavendra Reddy P
评论： Raghavendra Reddy P 2015-6-1
I have vector x contains 33-elements
x = [
1.0000
0.9974
0.9853
0.9793
0.9735
0.9588
0.9560
0.9461
0.9421
0.9385
0.9380
0.9372
0.9343
0.9333
0.9319
0.9306
0.9286
0.9280
0.9969
0.9933
0.9926
0.9920
0.9817
0.9751
0.9718
0.9572
0.9552
0.9462
0.9397
0.9362
0.9321
0.9291
0.9288]
>> t=[1:33];
>> plot(t,x)
gives you a graph, now i have a y vector which contains only 13 elements
y = [
1.0000
0.9974
0.9853
0.9712
0.9588
0.9360
0.9333
0.9295
0.9928
0.9763
0.9483
0.9397
0.9279]
now i wanted to draw graph on existing one such that elements values of y, which are near to x values should come same t-axis points. example:- y(4)=0.9712 is almost equal equal to x(5)=0.9735 at t=5, y(end)=0.9279 is equal to x(end)=0.9288 at t=33... hence i want y(4),y(end) on t=5,t=33.

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2015-6-1
y(end)=0.9279 is equal to x(end)=0.9288 at t=33
0.9729 is smaller than any x value, and is closest to x(18) which is 0.9280.
y(4)=0.9712 is almost equal equal to x(5)=0.9735 at t=5
0.9712 is closer to x(25) = 0.9718
The descriptive part about "near to x values" leads to this code:
plot(1:length(x),x,'r',interp1(x, 1:length(x), y, 'nearest', 'extrap'),y,'g.-')
which has each y value being drawn at the t value that corresponds to the x value that is closest to the y value.
Your rules about what is near enough do not appear to be well defined.
  1 个评论
Raghavendra Reddy P
Raghavendra Reddy P 2015-6-1
Thank you sir, since the above values are small fraction numbers i couldn't differentiate exactly the way i wanted. your coding is fine. i just wanted to draw y graph on same x-axis of x graph such that elements values of y and x are closer.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Discrete Data Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by