isolated word detection, comparing two audio files

Question

Ayush 2015-6-5

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/222566-isolated-word-detection-comparing-two-audio-files

评论： Anjaneyulu Challa 2016-4-15

i am trying to compare two audio files, one is user input and the second file is the pre-recorded sample (defined). I need to compare both, i have converted both .wav file from time domain to frequency domain. yet i cannot establish a way to compare both the files.

   Fs = 10000;   % Sampling Frequency (Hz)
  Nseconds = 1; % Length of speech signal
  fprintf('say a word immediately after hitting enter: ');
  input('');
  % Get time-domain speech signal from microphone
  y  = wavrecord(Nseconds*Fs, Fs, 'double');
x = fft(y);
% Get response until Fs/2 (for frequency from Fs/2 to Fs, response is repeated)
x = x(1:floor(Nseconds*Fs/2));
% Plot magnitude vs. frequency
m = abs(x);
f = (0:length(x)-1)*(Fs/2)/length(x);
plot(f,m);
xlabel('Frequency (Hz)');
ylabel('Magnitude');
% Get time-domain speech signal already recorded sample
y2=wavread('sample01_6k.wav','double');
x2 = fft(y2);
% Get response until Fs/2 (for frequency from Fs/2 to Fs, response is repeated)
x2 = x2(1:floor(Nseconds*Fs/2));
% Plot magnitude vs. frequency
m2 = abs(x2);
f2 = (0:length(x2)-1)*(Fs/2)/length(x2);

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Answer 1

Walter Roberson 2015-6-5

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/222566-isolated-word-detection-comparing-two-audio-files#answer_181651

fft() is for periodic signals. If the longer signal consisted of nothing other than the same word repeated over and over again exactly the same way then comparing the fft() might be useful.

You will need to use a technique that deals with analysis over short times rather than infinite. One technique is Short Time Fourier Transform. See for example http://www.mathworks.com/help/signal/ug/formant-estimation-with-lpc-coefficients.html