How do I put in a range of negative numbers?

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Tom
Tom 2011-11-25
回答： Disha Patel 2018-12-12
I've got this script: -
m=2
g=9.81
k=0.5
c=sqrt((m*g)/k)
v=[-6.264183904]
t=(-1*(c/2)*log((c+v)/(c-v)))/g
plot(v,t)
and I want my values for v to be equal to a range of values going from -c to 0. I can't seem to make it do it for some reason.

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采纳的回答

Image Analyst
Image Analyst 2011-11-25
Try linspace, like this:
m=2
g=9.81
k=0.5
c=sqrt((m*g)/k)
v=linspace(-c, 0, 100);
t=(-1*(c/2)*log((c+v)./(c-v)))/g;
plot(v,t, 'bo-');
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1])
Note that because v is now an array some of the slashes needed to be changed to dot slashes.
  2 个评论
Tom
Tom 2011-11-25
That's great thanks. I get the linspace command now I think. What's 'bo-'? And would you mind just explaining the bottom line a bit? Thanks again.
Walter Roberson
Walter Roberson 2011-11-25
'bo-' is Blue lines with circular ("o-shaped") markers, using solid lines to connect the points.
Outerposition is difficult to explain. You can read the documentation about it, http://www.mathworks.com/help/techdoc/ref/axes_props.html#OuterPosition but I find it difficult to manipulate Innerposition and Outerposition to get predictable results.

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更多回答（1 个）

Disha Patel
Disha Patel 2018-12-12
I have got this script :
close all;
clear all;
clc
n = -10:1:-1;
u(n)= 1;
p=(0.25).^(n).*u(n);
plot(n,p);
I want to scatter function "p" in negative side of the x axis so what should I do if I run this code the error seems like there should be positive and logical value of the variable "n" could anyone help me out of this?

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