Find the volume of a nx3 Dataset
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Hello everybody, I have an easy question:
I have seen this great explanation about how to integrate the volume underneath a set of nonuniformly spaced data: http://blogs.mathworks.com/videos/2009/09/08/integrating-to-find-the-volume-underneath-a-set-of-nonuniformly-spaced-data/
but the interpolation here it´s done between 0-1 because of his dataset. My question is: if my dataset has a large number of different values (like a ball), how should I do this interpolation? I have thought about to change the
interpZ(0.5,0.5) %test interpolation
vol = quad2d(interpZ,0,1,0,1) %volume should be close to 1
like this:
interpZ(¿?,¿?) %test interpolation
vol = quad2d(interpZ,min(min(z)),max(max(z)),min(min(z)),max(max(z)))
Thank you.
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Image Analyst
2015-6-13
You have to decide what constitutes the "volume". Let's say your N by 3 data are the (x,y,z) coordinates in a scatter cloud/cluster that looks roughly like a peanut. Now, is your 3D volume the bounding box of the peanut? Or do you want it to be the volume of only the peanut itself? Finding the bounding box of the whole peanut is trivial = just use max() and min() on each of the three dimensions, x, y, and z. If you want a peanut shaped volume, then you have to decide if some arbitrary (x,y,z) point is to be included inside the peanut or outside of it, so that if you have a regular grid (like a CT or MRI volumetric image) then you can find the volume of the irregular peanut shape.
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Image Analyst
2015-6-17
If you want the volume in real world units you have to know the width of a voxel. What is your field of view? What is the number of voxels across it? Divide those to get the real world units of a voxel - essentially the cross sectional area. See my attached spatial calibration demo.
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