generating a weibull channel on Matlab
7 次查看(过去 30 天)
显示 更早的评论
Hi,
I am new here.. I just have a doubt on how to create a Weibull channel on Matlab. For Rayleigh, I know it can be given as: h = 1/sqrt(2)*[randn(nRx(jj),N) + j*randn(nRx(jj),N)] where, nRx is the length i assumed and N is the number of bits in this case.
But how can I generate Weibull channel in the same manner ?
Please help me in this regards. That will be much appreciated.
Thanks and regards,
Raj.
0 个评论
采纳的回答
bym
2011-11-27
hw = lamda.*(-log(rand(nRx(jj),N)).^(1/beta))
where lamda & beta are your Weibull parameters. BTW you can generate your Rayleigh channel by using beta = 2
4 个评论
can
2017-5-22
What about Rician Channel? How can I generate Rician channel in the same manner ? Please help me, Thanks and regards.
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!