NaN in Neural network training and simulation; tonndata
20 次查看(过去 30 天)
显示 更早的评论
Hello,
I have two questions. Thank you very much for any inputs and ideas!!! 1) How to deal with NaN in Neural network training and simulation? The datasets I used as following. The input dataset is a 6*204 matrix with several NaNs. The output dataset is a 6*204 matrix with many NaNs. My simulation dataset is a 6*864000 matrix with many NaNs. I used nntool GUI to train network and do simulation. But the simulation results have numbers even for the simulation samples with all NaNs. I want to ask if there is a way I can set that NaN is not replaced by anything. Just keep it as NaN when do training and simulation.
2) When I try cell array generated by tonndata, the neural network treat the cell array as one sample, so there is no way to separate all samples into training data, test data, validation data. Anyone can share me why using cell array in neural network?
I googled but could not find a good answer or document about these two issues. Thank you very much for any inputs and help!
采纳的回答
Greg Heath
2015-6-22
Do not refer to NaN as " No value ". It stands for "Not a Number" and is just referred to as NaN pronounced as en-ay-en.
close all, clear all, clc
[ I N ] = size(x) % [ 6 5 ]
[ O N ] = size(t) % [ 6 5 ]
net = fitnet; % H=10
net.divideFcn = 'dividetrain'; % Not much data
Hub = -1+ceil((N*O-O)/(I+O+1)) % 1 H= 10 is overfitting: need overtraining mitigation
rng('default')
for i = 1:20
net = configure(net,x,t);
[ net tr ] = trainbr(net,x,t); %mitigate overtraining
y = net(x)
stopcrit{i,1} = tr.stop;
MSE(i,1) = mse(t-y);
end
lasty = y
% = [ 2.405 2.405 2.405 2.405 2.405
% 1.2 1.2 1.2 1.2 1.2
% 1.6819 NaN 0.676 NaN 1.559
% -1.605 -1.605 -1.605 -1.605 -1.605
% 1.5 1.5 1.5 1.5 1.5
% 1.067 NaN 1.9648 NaN 1.1768 ]
stopcrit1 = stopcrit{1}
% = Minimum gradient reached.
stopcrit = stopcrit % repmat(stopcrit1,20,1)
MSEp = MSE'
% MSEp = e-17 x [ ...
% 104.51 6.77 8.44 103.22 200.35 0.30 0.14
% 131.41 177.22 195.06 832.83 0.55 0.22 0.89
% 0.87 0.85 583.46 430.18 0.54 0.33 ]
3 个评论
Greg Heath
2015-6-23
Don't skip the calculation. It helps set an upper bound on the search for an optimal H. For example, it is desirable to have H << Hub.
更多回答(1 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Sequence and Numeric Feature Data Workflows 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!