Binning 2D set of coordinates
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I'm pretty new to MATLAB, so sorry if this seems easy. I've got a single long trajectory for a particle below. I have about 100,000 X and Y coordinates from which I've assembled the graph. I'm trying to create a density plot of the coordinates to show where the trajectory is most concentrated. I'm trying to create a density plot of the coordinates to show where the trajectory is most concentrated. I've got the second plot using the following code:
bins = 200;
binsizeX = 3/bins;
binsizeY = 1.2/bins;
xbins = -1.5:binsizeX:1.5;
ybins = -0.6:binsizeY:0.6;
[nx,idxx] = histc(X,xbins);
[ny,idxy] = histc(Y,ybins);
out = accumarray([idxx,idxy], 1);
figure(2);
hold on;
h=imagesc(xbins,ybins,out);hold on;
colorbar; hold on;
axis([-1.5 1.5 -0.6 0.6]); hold on;
But it seems that the density is shifted up and to the right for some reason? Any help is appreciated! Thanks!
回答（4 个）
alessandro
2016-10-13
编辑：Walter Roberson
2016-10-13
1 个投票
Old post, but will try to answer anyway, in case anybody else end up with same issue.
The easiest way to do what you are willing to do is to use hist3 function, with which binning resolution is user dependent and density matrix can be stored easily.
Katalin
2015-6-19
0 个投票
imagesc flips the image I think. This is from the help: imagesc(x,y,C) displays C as an image and specifies the bounds of the x- and y-axis with vectors x and y. If x(1) > x(2) or y(1) > y(2), the image is flipped left-right or up-down, respectively.
Image Analyst
2015-6-19
With images, since they are arrays, line 1 (row 1) is at the top, and the line numbers get bigger as you go down the screen. This is the standard custom with images.
With a plot, since it's like regular Cartesian coordinates, where the "y" value increases as it goes up the screen.
The right/left are not flipped, just the up/down. You could use flipud(out) to flip the image vertically before displaying it if you want the plot and image to look similar.
imagesc(xbins, ybins, flipud(out));
2 个评论
Akhil Ghanta
2015-6-19
编辑：Akhil Ghanta
2015-6-19
Well now, the density is just flipped. The slope of the ellipse is now negative. The big thing is that the density isn't centered like the original trajectory is in the original post.
Image Analyst
2015-6-20
Is the centroid supposed to be at (0,0)? Please attach your data file with the paper clip icon, along with code to read it in.
Walter Roberson
2015-6-19
out = accumarray([idxx,idxy], 1);
should be
out = accumarray([idxy,idxx], 1);
Height (y) is expressed as row number so the y index needs to be first.
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2015-6-19
2016-10-13
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