Subscript indices must either be real positive???

Question

Jay 2015-6-27

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/225536-subscript-indices-must-either-be-real-positive

评论： Jay 2015-6-27

采纳的回答： Stephen23

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What does the above mean?

I have a variable that is used to count the iterations,

That same variable is matrix row specifier in another matrix.

A_matrix=[0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0]
del_hat_xi(1,1) = 0                             % delta hat variables for A matrix population
del_hat_yi(1,1) = 0
del_hat_xj(1,1) = 0
del_hat_yj(1,1) = 0
del_hat_xk(1,1) = 0
del_hat_yk(1,1) = 0
coords = [1,NaN,5025.02600000000,1001.87500000000;2,NaN,5600,1500;3,NaN,5500,620;4,NaN,5100,620]
d_0_ij = [1,1,2,760.738862094609;2,2,3,885.663593019381;3,3,4,400;4,1,3,609.449601116450;5,1,4,389.165281469198]
d_0_row = 5
for r_cnt =1:d_0_row
      % peruse d_0_ij FROM and TO station columns and specify A matrix
      % columns to populate
      del_hat_xi = d_0_ij(r_cnt,2)-1
      del_hat_yi = d_0_ij(r_cnt,2)
      del_hat_xj = d_0_ij(r_cnt,3)-1
      del_hat_yj = d_0_ij(r_cnt,3)
      % populate A matrix with values from linearised equation.
A_matrix(r_cnt,del_hat_xi) =(coords(r_cnt,d_0_ij(r_cnt,3)) - coords(r_cnt,d_0_ij(r_cnt,2))) / d_0_ij(r_cnt,4)
end

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Stephen23 2015-6-27

Should Amatrix really be named A_matrix (or vice versa)?

Jay 2015-6-27

Sorry, that was a typographical error. Should be "A_matrix" Still throws the same error with the code being rectified.

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Answer 1

Stephen23 2015-6-27

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/225536-subscript-indices-must-either-be-real-positive#answer_184200

编辑：Stephen23 2015-6-27

Like a lot of mathematics, MATLAB indexing starts at one. On the first loop the value of del_hat_xi is zero, which gives the error.

You can discover this yourself by setting a break-point on the line where the error occurs, and then checking the values of the indices when it stops. If you do not know how to use the debugging tools in MATLAB, now is a good time to learn how!

Although there are no doubt several ways to resolve this by making changes to this algorithm, it might actually be a good idea to tell us exactly what you desired output is, and we can show you a more efficient way of programming it.