HELP to resolve this code

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Poonam
Poonam 2015-6-29
评论： Image Analyst 2015-6-29
m=original color image
en=enhanced color image
have written code for measure absolute mean brightness error(AMBE)
function E=eme(x,m)
em=mean2(x);
mm=mean2(m);
E=abs(em-mm);
end
Here E is absolute difference between mean brightness of two color images I think this code will take mean brightness of one channel of color image butcolor image has three channel so how will take the mean brightness value of all three channel

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回答（1 个）

Thorsten
Thorsten 2015-6-29
function d = brightnessdiff(I1, I2)
d = rgb2gray(I1) - rgb2gray(I2);
  2 个评论
Poonam
Poonam 2015-6-29
why should I convert it into rgb2gray i want mean brightness difference of color image
Image Analyst
Image Analyst 2015-6-29
Brightness is not very precisely defined. Using rgb2gray() will give you the "brightness". You could also use rgb2lab() and use the L channel, or rgb2hsv() and use the V channel. It depends on what you want. Or perhaps you want to convert to LAB color space and look at the Delta E (color difference) which takes into account the total color difference, not just the brightness component. For example Delta E (like in my File Exchange) takes hue and chroma (saturation) into account, as well as brightness, in determining a total color difference.

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