Putting similar named variables into one vector or structure

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Asher Metzger
Asher Metzger 2015-7-21
编辑： Stephen23 2019-6-19
Hi,
I'm trying with no succes to put variables that have the same construct into one vector: C_100, C_200 and so on into vedctor C. I also want to put Arrays of (44,2) with similar names into a structure: Q_100, Q_200 and so on into a structure Q. Is there a simple way to loop through it?
Thanks in advance, Asher
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Stephen23
Stephen23 2015-7-21
编辑：Stephen23 2015-7-21
It sounds like your .mat files have different data in them, and so the output of load has different fields in its structure. Structures with different fields cannot be concatenated together, thus the error. One possible solution is to use load's optional argument to only read the same variable/s from each .mat file. Here is a complete working example of how to do this:
A = [1,2,3];
save('temp1','A');
A = [4,5,6];
save('temp2','A');
A = [7,8,9];
B = NaN;
save('temp3','A','B'); % <- different number of fields!
D = dir('temp*.mat');
N = {D.name};
for k = numel(N):-1:1
S(k) = load(N{k},'A'); % Specify 'A' only
end
If you remove the 'A' from the load command then it give the same error as you are getting, but with this optional argument it will only load the A field, so no error. Here are some ways of accessing the data in the structure S:
>> S(2).A % indexing single element
ans =
4 5 6
>> horzcat(S(2:3).A) % subset indexing
ans =
4 5 6 7 8 9
>> vertcat(S.A) % all data
ans =
1 2 3
4 5 6
7 8 9
>> {S.A} % all into a cell array
ans =
[1x3 double] [1x3 double] [1x3 double]
And believe you me, this is much more reliable and faster than trying to use dynamically named variables!
Asher Metzger
Asher Metzger 2015-7-29
编辑：Asher Metzger 2015-7-29
Thanks!! again. Have been working with the structs. Very neat and comfortable. Here is a question that arose: I have 7 data files with the same variables. but on the seventh one I forgot to create one of them. I put them all in a struct: S(1), S(2) and so on. in a loop but the seventh one won't go in understandably because it doesn't have the same fields. So I added the variable (h) to the seventh mat file but for some reason it still won't be joined to the struct. I am attaching 7 of the files. the one named 7 won't be added to the other 2. I would love to understand the reason. this is the loop I wrote:
for i=1:7
aa=sprintf('NYT_outout_%d_years.mat',i);
S(i)=load(aa);
end
Thanks a lot in advance. Asher

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Stephen23
Stephen23 2015-7-21
编辑：Stephen23 2019-6-19

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Azzi Abdelmalek
Azzi Abdelmalek 2015-7-21
编辑：Azzi Abdelmalek 2015-7-21
v={'C_100','aze','C_200'}
C=regexp (v,'C_\d+','match')
idx=~cellfun (@isempty,C)
outc=C (idx)

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