Subscript indices must either be real positive integers or logicals

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Luis Meneses
Luis Meneses 2015-7-25
评论： Luis Meneses 2015-7-25
x = tudo(:,2)
y = tudo(:,1)
w = tudo(:,3)
% normalize ships
min_x = min(x)
max_x = max(x)
norm_nav = (x - min_x)/(max_x - min_x)
tudo_norm(:,1) = norm_nav
% normalize hours
min_y = min(y)
max_y = max(y)
norm_horas = (y - min_y)/(max_y - min_y)
tudo_norm(:,2) = norm_horas
% normalize poff
min_w = min(w)
max_w = max(w)
norm_poff = (w - min_w)/(max_w - min_w)
tudo_norm(:,3) = norm_poff
% matrix A
A(:,1) = tudo_norm(:,3)
% matrix B
B(:,2) = norm_nav
B(:,3) = norm_horas
B(:,1) = 1
% matrix C
C = sym('C', [3 1])
% coefficients
transposed = B.'
BB = B.' * B
inverse = inv(B.' * B)
C = inv(B.' * B) * B.' * A
% W = D + AX + BY
T = C(1,1) + C(2,1) * norm_nav + C(3,1) * norm_horas
% RMSE
erro = T - norm_poff
sqerr = erro.^2
msqerro = mean(sqerr)
rmse = sqrt(msqerro)
% standard deviation
d_padrao = std(T)
% (SSE)
sse = sum(erro.^2)
xx = sse / (tamanho-3)
%-------------------------------------------
% TESTING
% Enter desired data
Navios = 3
Horas = 1
% New max an min?
if Navios > max(x) % max e min de x
max(x) = Navios
else
if Navios < min(x)
min(x) = Navios
end
end
if Horas > max(y) % max e min de y
max(y) = Horas
else
if Horas < min(y)
min(y) = Horas
end
end
% normalize new
navio = (Navios - min_x)/(max_x - min_x)
hora = (Horas - min_y)/(max_y - min_y)
max_navio = max(x)
max_hroas = max (y)
max_poff = max(w)
W = C(1,1) + C(2,1) * navio + C(3,1) * hora
% RMSE
erro = W - norm_poff
sqerr = erro.^2
msqerro = mean(sqerr)
rmse = sqrt(msqerro)
% (SSE)
sse = sum(erro.^2)
xx = sse / (tamanho-3)
POFF = (W*(max_w - min_w)) + min_w
Hello guys, I'm currently developing a code to the prediction of some data. However I have a problem. When intend to test the code, and enter the desired data, when I type the variable "Navios" = 1 the following error appears:
Subscript indices must either be real positive integers or logicals Error in ==> Modelo_2VAR at 90      if horas <min (y)
I do not understand why this error appears.
Someone help me?

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2015-7-25
There is a problem with the lines of code containing:
max(x) = Navios
min(x) = Navios
max and min are built-in functions, you can't use them as variables

更多回答（1 个）

Walter Roberson
Walter Roberson 2015-7-25
if Navios > max_x % max e min de x
max_x = Navios
else
if Navios < min_x
min_x = Navios
end
end
if Horas > max_y % max e min de y
max_y = Horas
else
if Horas < min_y
min_y = Horas
end
end
  1 个评论
Luis Meneses
Luis Meneses 2015-7-25
Thank you.
But nevertheless, when I change the value of "Navio" from 0, 1, 2 and 3, the result does not change ... Why does it happen?

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