Need help alternating a code

1 次查看（过去 30 天）
Sha S
Sha S 2015-7-29
回答： Sean de Wolski 2015-7-29
Hi, I had... a = [ 2 5 1; 3 6 2; 3 4 1; 9 4 2; 8 3 1; 3 2 2; 9 5 2; 4 8 1]
Notice how the last column follows a pattern of 1, 2,1,2..and so on. The 7th row however has a 2 in the last column just like the 6th row before...thus does not follow the pattern. The code below deletes the 7th row.
[m,n] = size(orderedheelstrikes);
expected = orderedheelstrikes (1,n); % initialize expected value in 1st row
x = false(m,1); % initialize the deletion flag array
for k=1:m
if( orderedheelstrikes(k,n) ~= expected )
x(k-1) = true; % if not as expected, mark for deletion
else
expected = 3 - expected; % if as expected, update expected
end
end
orderedheelstrikes(x,:) = []; % delete the unexpected pattern rows
Now I have changed some of my values and the last row follows a pattern of 3,4,3,4,3...etc. I was just wondering what I need to change in this code to accommodate for the new pattern. I want the code to do the same thing as before in terms of deleting in the example below the 7th row because the 4 is repeated.
Ex: a = [ 2 5 3; 3 6 4; 3 4 3; 9 4 4; 8 3 3; 3 2 4; 9 5 4; 4 8 3]
Thanks!

请先登录，再回答此问题。

回答（1 个）

Sean de Wolski
Sean de Wolski 2015-7-29
expected = [3; 4];
badrow = find(~bsxfun(@eq,reshape(a(:,end),2,[]),expected),1,'first')
If you're doing this row by row the above should work

类别

在 Help Center 和 File Exchange 中查找有关 Graph and Network Algorithms 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by