Can strsplit be applied to a matrix?

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TingTing
TingTing 2015-8-10
评论： Walter Roberson 2015-8-13
Hi, I am used strsplit to take out 1 from string of "1: abc". I have to loop each string and that takes time. Is there anyway that I can apply this function on a column or a matrix? Thanks!

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回答（1 个）

Walter Roberson
Walter Roberson 2015-8-10
Have you considered using regexp() or regexprep() ?
  2 个评论
TingTing
TingTing 2015-8-12
Hi, thanks for tip! However, I don't really get it. strsplit does the job, though it has to loop. I would like to have something that applies to the whole column without looping. I am not sure if regexp works, and even if that works, it still works per string, doesn't it?
Walter Roberson
Walter Roberson 2015-8-13
Is your data a char array? If so then just access columns 2 onward
without_leading_digit = TheData(:,2:end);
Or is it only to be removed if it is '1' but not if it is a different digit? Or is it only to be removed if it is a series of digits followed by a colon? Is the colon to be left in place? Is the space to be left in place? If you are using a char array then what is the expected result if the resulting strings would be a different size? If you are using a char array then would it be acceptable for trailing spaces to be deleted along the way?
If you are using a cell array of strings, then if you are removing a fixed number of characters remember there is always cellfun
without_leading_digit = cellfun(@(S) S(2:end), TheDataCell, 'Uniform', 0);
Did you consider reading the documentation of regexp() and regexprep?
If you want the input split at the colon then do you want both parts or do you want everything after the colon or everything after the space after the colon?
>> t = {'1: zip', '23: frodo'}; regexprep(t, '[^:]+:\s+', '')
ans =
'zip' 'frodo'

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