How to derive the state-space model in which the second derivative of the output of the system is needed?

4 次查看(过去 30 天)
Dear all:
My transfer function is:
Y/U = (a1s+a0)/(b4s^4+b3s^3+b2s^2+b1s); s is the laplace symbol, U is the single input, and Y is the single output.
Now I want a state-space model where I can have the second derivative of Y, which is dotdot(y) (dotdot is second derivative with respect to time).
Any help is appreciated!

采纳的回答

Sebastian Castro
Sebastian Castro 2015-8-11
If the above is the TF for Y, then the second derivative of Y is just Ys^2, so the TF would be:
Ys^2/U = (a1s^3+a0s^2)/(b4s^4+b3s^3+b2s^2+b1s);
In MATLAB terms, you could either mathematically rework these into a state-space, or if you're lazy like me, make both the transfer functions and then convert to State-Space. NOTE: This requires Control System Toolbox.
Y = tf([a1 a0],[b4 b3 b2 b1 0]);
Ydd = Y*tf('s')^2;
G = [Y;Ydd];
Gss = ss(G);
... and there you have it, a state-space with 2 outputs: The first being Y, the second being Y doubel dot. Hope this helped.
- Sebastian
  6 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Dynamic System Models 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by