How to write this simple script correctly?
1 次查看(过去 30 天)
显示 更早的评论
Hi I have
s=[1 0 1;0 0 0];
b=[2 3 4];
I would like to have this as a result
c=[nan 3 nan;2 3 4]
I mean replace 1 by nan and o by b.
for r= 1:3
s_ind = find(s(:,r) == 1);
s(s_ind)=nan;
m(:,r)=s
a_ind = find(s(:,r) == 0);
% I don't know how to replace for 0 from matrix b??
end
any help would be appreciated in advance.
0 个评论
采纳的回答
更多回答(1 个)
Star Strider
2015-8-11
You can use logical indexing, although you need two separate steps to assign the elements of ‘b’ and ‘NaN’ to ‘c’ because you have two separate conditions.
One possibility:
s=[1 0 1;0 0 0];
b=[2; 3; 4];
mb = repmat(b', 2, 1); % Create Matrix Matching ‘s’ From ‘b’
c = s; % Create ‘c’
c(~c) = mb(~c); % Assign Elements Of ‘mb’ To Zero Elements Of ‘c’
c(c==1) = NaN; % Assign ‘NaN’ To ‘c’ = 1
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!