ind2sub output dimension

1 次查看(过去 30 天)
My question is regarding the output of the ind2sub function. In my code, since the input dimention of ind2sub changes, i should expect the output dimention to change. But a code like this is not working.
B = rand(6,6,6);
A(1:ndims(B)) = ind2sub(size(B),56);
The output of the above code is [56 56 56] while I'm expecting something like [2 4 2].
Any suggestion?

采纳的回答

Fangjun Jiang
Fangjun Jiang 2011-12-11
Follow the same clue in the answer to your other question, you can do the following:
B=rand(4,5,6);
Ind=(20:25).';
n=ndims(B);
Sub=cell(1,n);
[Sub{:}]=ind2sub(size(B),Ind)
SubMatrix=cell2mat(Sub)
Sub =
[6x1 double] [6x1 double] [6x1 double]
SubMatrix =
4 5 1
1 1 2
2 1 2
3 1 2
4 1 2
1 2 2

更多回答(1 个)

bym
bym 2011-12-10
you need multiple assignments for that function.
[r,c,p]=ind2sub(size(B),56)
r =
2
c =
4
p =
2
  2 个评论
Paulo Silva
Paulo Silva 2011-12-10
that one was bugging me for some time, +1 vote
Mohsen  Davarynejad
Mohsen Davarynejad 2011-12-10
But as I've mentioned, the output dimention is changing. So I do not know if the I need three variables, in your case r, c, p, of if I need more.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Directed Graphs 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by