plotting lines
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i have a simple ques that if i have z-plane having x and y axes,and i express z=x+i*y,and x if fixed let say 5 any y=0:10 then how can i plot this thing,please guide me,i m waiting for reply
回答（3 个）
bym
2011-12-11
y = 1:10;
x=5*ones(size(y));
z=x+i*y;
plot(real(z),imag(z))
1 个评论
Walter Roberson
2011-12-11
That will not be able to show the values of x and y on the axes.
Mohsen Davarynejad
2011-12-11
y = [0:.1:10]
plot(5,y)
xlabel('Re')
ylabel('Im')
3 个评论
Walter Roberson
2011-12-11
What about z? y is not the imaginary quantity.
My recollection is that if you plot a scalar x against a row vector y, that you end up with a single (probably invisible) point, but that if you plot a scalar x against a column vector y, you will get a line. It is, my memory says, an exception to the "row vector is automatically converted to column vector" rule, and happens because the size of x (i.e., one) happens to match the first dimension of y (i.e., one for a row vector)
Mohsen Davarynejad
2011-12-11
If z = x + yi, then x is the "real part" and y is the "imaginary part". When x is a constant and y is vector, then you will have line in the complex plane. No?
http://en.wikipedia.org/wiki/Imaginary_number
Walter Roberson
2011-12-12
z might be a line in the complex plane, but plot(5,y) does not involve z at all, and plot(5,z) would be refused because it is not allowed to plot complex data except through plot(z) which in turn is the same as plot(real(z),imag(z)) -- real vs imaginary.
Walter Roberson
2011-12-11
y = 0:10;
x = 5 * ones(size(y));
z = x + i * y;
Now, if "i" were a real-valued constant, you would then use
plot3(x, y, z)
However, "i" is the complex constant, so you have a line in complex space, and there is no way to draw that in one step. Instead you would need to use something like,
plot3(x, y, real(z), 'r', x, y, imag(z), 'g', x, y, abs(z), 'b')
or perhaps plot 3 separate images using subplot()
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2011-12-11
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